Ok! I thought it were more complicated than that... It seems to work perfectly. Trigonometry is too old for me... I have to re-work on it.
Thx a lot! Cheers, François T. ------------------------------- On 1 juil, 19:09, Rossko <[email protected]> wrote: > > ... I suppose "lat" is the latitude of the center > > point. > > "lat" is the latitude of wherever it is you are trying to calculate > pixels-per-whatever. Bear in mind it'll only be truly valid at that > place, not all over the map, but unless you are looking at large > chunks of the globe, it will do. > > > But I don't know what is 40075017 ... > > Circumferance of the earth in meters, you don't need that. > > > and how can I change this > > formula to get degree per pixel in north/south axe... > > The text explains that the interesting part for you, which is a factor > converting pixels-per-degree form the easy north-south version to the > harder east-west, is accomplished by cos(lat) > > Pixels per degree-EW = cos(lat) * pixels per degree-NS ?? > > Not a maps API question, basic trigonometry. > > cheers, Ross K --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Google Maps API" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/Google-Maps-API?hl=en -~----------~----~----~----~------~----~------~--~---
