On 9 November 2010 15:59, xelawho <[email protected]> wrote:
>> Yes. Hide all the ones you aren't showing.
>
> ... which looks like it might take a little more than:
>  else {
>          gpolygons[i].hide(all);
>        }
>
> a clue, please?

I suggest a glance at the documentation.
http://code.google.com/apis/maps/documentation/javascript/v2/reference.html#GPolygon.hide

There is no "(all)", and you have a clue already with
gpolygons[i]
-- just loop through all the members of the gpolygons[] array and
.hide() them all.

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