As I said, if you talk "long distances", the earth is not a "plain" field. If you'd rather have him use Haversines formula, why not quote it here. Otherwise, for distances under a few hundred miles (other than at Latitude 90 or -90) my formula should work (assume latitude is "y" and longitude is "x").
On Sep 20, 7:59 pm, Rossko <[email protected]> wrote: > > distance = square root ( (x2 - x1) squared + (y2-y1) squared )) > > Sure, but that doesn't work well for lat/long coordinates. Haversine > Formula is generally used. > > > Note that you need to do this arithmetic for every point that's within > > the square (lowest x, lowest y) to (highest x, highest y), but you can > > do this query in SQL and then eliminate the ones outside the circle. > > Yes, if searching a large database a simple "bounding box" query can > be used to give candidates for more complicated further testing. -- You received this message because you are subscribed to the Google Groups "Google Maps JavaScript API v3" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-maps-js-api-v3?hl=en.
