On Dec 9, 8:17 am, TeamSancheZz <[email protected]> wrote: > Hey Larry, would you be kind enough to point in the direction of where > to find the documentation on the new Driving Directions Web Service? I > am currently using the directions service, but I really think the web > service will work better with my complex VB code.
There is a reference to it on the right hand side of the documentation for the API... http://code.google.com/apis/maps/documentation/webservices/ http://code.google.com/apis/maps/documentation/directions/ -- Larry > > Thanks! > > On Dec 8, 9:27 am, "[email protected]" <[email protected]> > wrote: > > > > > On Dec 8, 6:14 am, "[email protected]" <[email protected]> > > wrote: > > > > Hi, I am using Classic ASP: > > > That is server side and not particularly relevant to the Google Maps > > Javascript API > > > > and have just got my API key. > > > v3 of the Google Maps Javascript API doesn't require a key, v2 does. > > That group is:http://groups.google.com/group/google-maps-api > > > > Now i'd like to figure out the code to give me teh distance between > > > two postcodes > > > 1. A postcode is not a point, it is (usually) a region. You need to > > figure out if you mean the center, the centroid, the closest border or > > some other point in the postcode. > > > 2. Do you want driving directions or "straight line, as the bird > > flies" distance? > > > The Google Maps APIs provide a driving directions service, and there > > is now a web service (for use with a map). > > > > and use this in my ASP page. > > > On the server or in the client (browser)? > > > -- Larry > > > > Thanks- Hide quoted text - > > > - Show quoted text -- Hide quoted text - > > - Show quoted text - -- You received this message because you are subscribed to the Google Groups "Google Maps JavaScript API v3" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-maps-js-api-v3?hl=en.
