There are some console.log() calls in your code. 'console' is a
Firebug object.
You can comment those lines away or you can create a dummy
console.log() in the beginning of your code.
if (console == "undefined"){
console = {};
console.log = function(){};
}
That doesn't disturb the console of Firebug.
--
You received this message because you are subscribed to the Google Groups
"Google Maps JavaScript API v3" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/google-maps-js-api-v3?hl=en.
