Sorry, heh, I keep mis-reading your original URL. Here you go: *set* myScript *to* "curl -G ' https://spreadsheets.google.com/feeds/list/0At<https://spreadsheets.google.com/feeds/list/key=0At...key> .../od6/public/basic/'"
*set* myData *to* (*do shell script* myScript) -Vic On Tue, Feb 15, 2011 at 3:07 PM, Joe Mathia <[email protected]>wrote: > ....SHBLNEE/od6/public/basic'" > > Still no luck. > > Thanks for your patience! > > Joe > On Feb 15, 2011, at 1:58 PM, Vic Fryzel wrote: > > Okay, and remove the rowID=3, I think then you should be good. > > -Vic > > > > On Tue, Feb 15, 2011 at 2:55 PM, Joe Mathia <[email protected]>wrote: > >> I'm sorry, I guess I'm still misunderstanding. >> >> curl -G ' >> https://spreadsheets.google.com/feeds/list/key=0AtJ7HjzM...truncated...5SHBLNEE/od6/public/basic/rowID=3 >> ' >> >> ...still gives me ""spreadsheet at this URL could not be found." >> >> Joe >> >> >> On Feb 15, 2011, at 1:45 PM, Vic Fryzel wrote: >> >> Sorry I was unclear. I meant: in your original URL, replace the string >> "worksheetId=0" with the string "od6" >> >> -Vic >> >> >> >> On Tue, Feb 15, 2011 at 2:44 PM, Joe <[email protected]> wrote: >> >>> Replacing "/public/basic/rowID=3"? This gives me "Invalid request URI". >>> >>> Tacking it on at the end of the string, e.g., " >>> /worksheetId=0/public/basic/rowID=3/od6" gives me the invalid URL >>> message. >>> >>> Thanks! >>> >>> >> >> > >
