Hi Water2Oil, Check out the RFC for XMPP http://www.ietf.org/rfc/rfc3921.txt have a look at section 5.1.6 and section 8 it has the details which ur looking for. I am sure it will help you.
Regards, Swanand On 10/25/07, water2oil <[EMAIL PROTECTED]> wrote: > > > Hi, > > First ,take the following steps: > 1, Running the call example in libjingle with "-d" option (for > example, log in as [EMAIL PROTECTED]) > > 2, then [EMAIL PROTECTED] send a request to add me as his/her friend > > the problem is : > > I receive nothing infomation on screen, so how do I know that > [EMAIL PROTECTED] wants to add me now????? > > maybe we can say in another way: > 1, if I want to add someone else as my friend, we can send > <iq type='set'> > <query xmlns='jabber:iq:roster'> > <item jid='[EMAIL PROTECTED]'/> > </query> > </iq> > to "our server". but "our server" must sends something to notify the > "someone else". > what infomation is sent by "our server"? OR what information "someone > else" receives? > > I don't know if my expression is clearly, forgive my poor english. > > Anyone would give me some hints? thanks in advance. > > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "google-talk-open" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/google-talk-open?hl=en -~----------~----~----~----~------~----~------~--~---
