Hello everyone;
I try to use the TablePatternFormat to have links (with a table) on
external web page but i don't succeed;
I do this :
var formatter = new google.visualization.TablePatternFormat('<a href="?
url={1}" target="_blank">{0}</a>');
With my iGoogle gadget, i get this :
1 | Test | www.adobe.com
etc.. with a link on the word "Test" like this : "http://
110.gmodules.com/ig/ifr?url=www.adobe.com"
And my problem is that i try to delete this "http://110.gmodules.com/
ig/" to open the web page adobe.com in an external window, is it
possible ?
Thanks by advance,
Mathieu
My code;
function draw(response) {
if (response.isError()) {
alert("Error in query")
}
var ticketsData = response.getDataTable();
var table = new google.visualization.Table
(document.getElementById('patternformat_div'));
var formatter = new google.visualization.TablePatternFormat('<a
href="?url={1}" target="_blank">{0}</a>');
formatter.format(ticketsData, [0,1]); // Apply formatter and
set the
formatted value of the first column.
var view = new google.visualization.DataView(ticketsData);
view.setColumns([0]); // Create a view with the first column
only.
table.draw(ticketsData, {allowHtml: true, showRowNumber:
true});
}
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