This is indeed a strange behavior...
Two things I can suggest to you for now:
1. Try seeing if it persists when you remove the event handlers on the sort.
2. If you want me to help you debug, you have to send me a version without
calls to your php cause obviously I can't do them cross-domain..

- VizBoy.

On Fri, Mar 20, 2009 at 2:39 PM, [email protected] <
[email protected]> wrote:

>
> I could really need some help, i am lost with this problem and i have
> got no idea ho to fix this...
> Id really appreciate any help!
>
> thanks
>
> On Mar 19, 10:28 am, "[email protected]"
> <[email protected]> wrote:
> > Well, this is pure js, isnt it? It simply parses the JSON and creates
> > how can i give the object a diffrent name each time it is initialized?
> > Something like an iterator...
> > This is kinda wierd, that this doesnt work out of the box.
> >
> > Well i think it is easier to give you the link:
> http://clients.station.ch/hardwarelist/
> >
> > On Mar 18, 3:47 pm, VizBoy <[email protected]> wrote:
> >
> > > Please try to generate a simple pure-javascript example.
> > > There shouldn't be a problem with creating multiple tables.
> > > Try to give them different names, although I don't see the problem with
> > > giving them the same name.
> > > Anyway, once you have a working pure-javascript example, we can help
> you
> > > debug it.
> >
> > > Regards,
> > >     VizBoy.
> >
> > > On Wed, Mar 18, 2009 at 11:25 AM, [email protected] <
> >
> > > [email protected]> wrote:
> >
> > > > Someone got some ideas?
> >
> > > > On Mar 17, 4:46 pm, "[email protected]"
> > > > <[email protected]> wrote:
> > > > > I am parsing JSON generated by php. This is how i populate the
> table:
> >
> > > > >                 fulllist['groups'].each(function(fulllist, index){
> > > > >                         var data = new
> google.visualization.DataTable();
> > > > >                         groups = fulllist;
> > > > >                         groups['fields'].each(function(field,
> index){
> > > > >                         data.addColumn('string', field.field_name);
> > > > >                         });
> > > > >                         data.addColumn('string', 'delete');
> > > > >                         if(groups['items'] != null){
> > > > >                                 groups['items'].each(function(item,
> > > > rowindex){
> > > > >                                         data.addRows(1);
> >
> > > > item['values'].each(function(value, index){
> > > > >
> data.setCell(rowindex,
> > > > index, value.value, '<span
> > > > > class="valueedit" id="valueedit_'+ value.value_id +'">' +
> value.value
> > > > > + '</span>');
> > > > >                                         });
> > > > >                                 });
> > > > >                         }
> > > > >                         data.sort([{column: 0}]);
> > > > >                         var table = new
> > > > google.visualization.Table(document.getElementById
> > > > > (fulllist.id));
> > > > >                         table.draw(data, {showRowNumber: false,
> > > > allowHtml: true});
> > > > >                 });
> >
> > > > > On Mar 17, 4:34 pm, rcrisman <[email protected]> wrote:
> >
> > > > > > Can you give us an example. and how are you generating the data.
>  PHP,
> > > > > > Java????
> >
> > > > > > On Mar 17, 11:26 am, "[email protected]"
> >
> > > > > > <[email protected]> wrote:
> > > > > > > hi
> > > > > > > I am generating multiple tables dynamically.  my problem is
> that only
> > > > > > > the last of these tables is sortable.
> > > > > > > how could i solve this problem? if it helps: i use the same
> name for
> > > > > > > the object each time i intialize the datatable.
> >
> > > > > > > thanks in advance
> >
>

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