I've tried that method as well:
var query = new google.visualization.Query("http://some-server.com/
api");
console.log("about to send query");
query.send(function(response){
console.log("in response function");
if (response.isError()) {
alert(response.getMessage());
return;
}
var data = response.getDataTable();
...
});
The "about to send query" message is logged to the console but the "in
response function is not. Instead, I still get the Uncaught Error
message:
about to send query
Uncaught Error: google.visualization.Query: Internal Server Error
[500] -
default,browserchart,columnchart,barchart,piechart,table,gauge,annotatedtimeline
+en_US.I.js:151
Same thing if I move the console.log to after the if statement:
query.send(function(response){
if (response.isError()) {
alert(response.getMessage());
return;
}
console.log("in response function");
var data = response.getDataTable();
...
});
Really appreciate your time and your help!
Les
On Jun 27, 6:33 am, Jinji <[email protected]> wrote:
> The query.send() function doesn't throw exceptions. Instead, in your
> response function (the one you pass to query.send), you should do:
>
> if (response.isError()) {
> alert(response.getMessage());
> return;}
>
> dataTable = response.getDataTable();
>
> I hope that helps.
>
> On Thu, Jun 24, 2010 at 7:13 AM, lesfreeman <[email protected]>wrote:
>
>
>
> > Hello,
> > I'm trying to catch server errors and display a custom error message.
> > Unfortunetly, I can't seem to catch the error on the JS side. Here's
> > the short version of my code:
>
> > try{
> > var query = new google.visualization.Query("http://some-server.com/
> > api");
> > query.send(function(response){
> > //some stuff gets done here
> > });
> > }catch(e){
> > console.log(e.name+" "+e.message);
> > }
>
> > Unfortunately, the error does not get caught. I my JS console I get:
>
> > Uncaught Error: google.visualization.Query: Internal Server Error
> > [500]
>
> > If I throw a custom error in the try block, it gets caught.
>
> > Any ideas?
>
> > Thanks
> > Les
>
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