this means that you cannot select and count the same column. try selecting the following:
select COL1, count(COL2) where COL2="X" group by COL1 if it does not help, here is a sample http://jsfiddle.net/TheNez101/pKjDa/ On Thu, Nov 17, 2011 at 2:57 PM, Dan <[email protected]> wrote: > Thanks for your help but I can't seem to get this working. > > select COL1, count(COL1) where COL2="X" group by COL1 > > Was hoping that this would be the equivalent to distinct but instead > returns the following error: > Column [COL1] cannot be selected both with and without aggregation in > SELECT. > > -- > You received this message because you are subscribed to the Google Groups > "Google Visualization API" group. > To view this discussion on the web visit > https://groups.google.com/d/msg/google-visualization-api/-/aFrJAyMHTTQJ. > > To post to this group, send email to > [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/google-visualization-api?hl=en. > -- You received this message because you are subscribed to the Google Groups "Google Visualization API" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-visualization-api?hl=en.
