I guess a better question is: what do you want your dropdown to list and
what do you want to happen when someone selects something in the list?
On Sunday, July 8, 2012 6:54:22 AM UTC-4, Adam Hardarson wrote:
>
> Ok, but I havn't gotten anywhere really... :-/
>
> ------------------------------------------------------------------
> if(!empty($_POST['first']) && !empty($_POST['second']) &&
> intval($_POST['first']) !== intval($_POST['second'])){
> $first = $_POST['first'];
> $second = $_POST['second'];
> $ord = ($second <= $first) ? 'DESC' : '';
> $r = mysql_query("SELECT * FROM MCI WHERE Id = $first OR Id = $second
> ORDER BY Id $ord");
> if(mysql_num_rows($r) == 2){
> while($d = mysql_fetch_array($r)){
> $arr[] = $d;
> }
> $output = createHTML($arr);
> }else{
> $output = "The values must be different and exist in the list. " .
> $output;
> }
> }
>
> $first = $arr[0];
> $second = $arr[1];
>
> $firstdata = json_encode($arr[0]);
> $seconddata = json_encode($arr[1]);
> ------------------------------------------------------------------
>
> My print json looks like
> this
> {"0":"7","Id":"7","1":"test","Foretag":"test","2":"44","Variabel_namn_4":"44","3":"34","Variabel_namn_5":"34","4":"64","Variabel_namn_6":"64"}
>
> So I have to format it the right way but I can't figure out how...
>
> If I want to show a simple bar chart with these
> columns "Variabel_namn_5":"34","Variabel_namn_6":"64" How should I proceed?
>
> Many thanks for taking time helping me out! :)
>
> Cheers
> Adam
>
>
>
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