Thanks for your solution with the cases, it worked very well.

Actually I already have a PHP script which creates the JSON file. On the 
website I can select which columns I want to have and the script creates 
the JSON file based on the created query. 

At the end of the script I do this:
    $fp = fopen('resultsOwnTable.json', 'w');
    fwrite($fp, json_encode($responseTable));

So basically I could just save do this?
      $table = json_encode($responseTable)
And use this to populate my DataTable in Javascript?

Am Freitag, 17. August 2012 05:09:10 UTC+2 schrieb asgallant:
>
> You might want to consider building a PHP script that will query your 
> database for you and output the data in the DataTable JSON format (or you 
> could try out the 3rd-party PHP 
> library<http://code.google.com/p/mc-goog-visualization/wiki/UserDocumentation>that
>  implements the Google Query interface).
>
> If you don't want to do either of those, you could make a quick-fix change 
> to the PHP file to make it accept a parameter via the url and select the 
> JSON file based on that:
>
> <?php
> // get the index of the file to output
> $index = $_GET['index'];
>
> // select the file based on $index
> switch ($index) {
>     case 0:
>         echo file('/path/to/file_0.json');
>         break;
>     case 1:
>         echo file('/path/to/file_1.json');
>         break;
>     case 2:
>         echo file('/path/to/file_2.json');
>         break;
>     case 3:
>         echo file('/path/to/file_3.json');
>         break;
>     .
>     .
>     .
>     case n:
>         echo file('/path/to/file_n.json');
>         break;
> }
> ?>
>
> You then choose the file to grab like this:
>
> var jsonData = $.ajax({
>     url: "getData.php?index=3",
>     dataType: "json",
>     async: false
> }).responseText;
> var data = new google.visualization.DataTable(jsonData); 
>
> The selector doesn't have to be "index" and it doesn't have to be numeric 
> - as long as you can map the request from the js end of things to a file on 
> your server, it will work.
>
> On Thursday, August 16, 2012 6:46:21 PM UTC-4, Chriggi wrote:
>>
>> Hello,
>>
>> I have a lot of json-files with different data from my database and want 
>> to populate my datatables with them. Currently I'm using the method 
>> described here: 
>> https://developers.google.com/chart/interactive/docs/php_example
>>
>> Basically I do this:
>>
>> var jsonData = $.ajax({
>>    url: "getData.php",
>>    dataType:"json",
>>    async: false
>>     }).responseText;
>> var data = new google.visualization.DataTable(jsonData);
>>
>> In getData.php there are just these 2 lines:
>> $string = file_get_contents("results.json");
>> echo $string;
>>
>> The problem here is, with one .php-file I can only get one JSON. So if i 
>> have for example 10 different charts with 10 different datatables created 
>> from different JSONS I need 10 .php-files. Isn't there a better solution 
>> for this?
>>
>>

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