Thank you very much, that helped! Now I'll use other chart options to fine
tune it a bit to look similar to my excel charts.
Really appreciate the help asgallant!
On Wednesday, October 17, 2012 10:31:40 AM UTC-7, asgallant wrote:
>
> D'oh! My mistake, I did change something else. The (float) typing
> converts null into 0, so you have to test for null and handle it specially.
> In your php file, the while loop should look like this:
>
> while($r = mysql_fetch_assoc($sth)) {
> $temp = array();
> $temp[] = array('v' => (float) $r['PsiBar']);
> $temp[] = array('v' => (is_null($r['prodPerct1'])) ? null : (float)
> $r['prodPerct1']);
> $temp[] = array('v' => (is_null($r['prodPerct2'])) ? null : (float)
> $r['prodPerct2']);
> $temp[] = array('v' => (is_null($r['prodPerct3'])) ? null : (float)
> $r['prodPerct3']);
> $rows[] = array('c' => $temp);
> }
>
> although, since your data is already in numerical form (and thus you don't
> have to force it to be type float), you can go with the simpler:
>
> while($r = mysql_fetch_assoc($sth)) {
> $temp = array();
> $temp[] = array('v' => $r['PsiBar']);
> $temp[] = array('v' => $r['prodPerct1']);
> $temp[] = array('v' => $r['prodPerct2']);
> $temp[] = array('v' => $r['prodPerct3']);
> $rows[] = array('c' => $temp);
> }
>
> It's also a good idea to force the mime type to application/json by
> setting the header, before you echo the json:
>
> header("Content-type: application/json");
> echo $jsonTable;
>
> On Wednesday, October 17, 2012 10:54:15 AM UTC-4, asgallant wrote:
>>
>> I used your code exactly as it appears in the files you posted, except
>> for the modifications mentioned. I didn't save a copy, though, so I can't
>> post them back. I'll see if I can duplicate it later today.
>>
>> On Wednesday, October 17, 2012 10:11:01 AM UTC-4, Jose wrote:
>>>
>>> Asgallant, I tried it again and still the same results, although I did
>>> add that var option but it didn't help. I'm wondering if its something else
>>> in your scripts/code that is different than mine. If you could post those,
>>> that would be great.
>>> As another non sufficient way, could three separate SQL calls be made
>>> then plot the results onto the same chart?
>>>
>>> On Tuesday, October 16, 2012 10:16:00 AM UTC-7, asgallant wrote:
>>>>
>>>> I duplicated your table and ran the query, and Method 2 looked right to
>>>> me. I had to make 1 small change to the SQL to make it run (but that
>>>> could
>>>> be a quirk of my MySQL install), and 1 change to the chart options. The
>>>> SQL looked like this:
>>>>
>>>> SELECT
>>>> foo.PsiBar,
>>>> IF(prodPerct1 = 0, null, foo.prodPerct1) as prodPerct1,
>>>> IF(prodPerct2 = 0, null, foo.prodPerct2) as prodPerct2,
>>>> IF(prodPerct3 = 0, null, foo.prodPerct3) as prodPerct3
>>>> FROM (
>>>> SELECT
>>>> PsiBar,
>>>> SUM(IF(id_sample = 1, prodPerct, null)) AS prodPerct1,
>>>> SUM(IF(id_sample = 2, prodPerct, null)) AS prodPerct2,
>>>> SUM(IF(id_sample = 3, prodPerct, null)) AS prodPerct3
>>>> FROM tbl_dilution
>>>> GROUP BY PsiBar
>>>> ) AS foo
>>>>
>>>> and I set the "interpolateNulls" chart option to true:
>>>>
>>>> var options = {
>>>> title: 'Line Chart Test',
>>>> interpolateNulls: true
>>>> };
>>>>
>>>>
>>>> On Tuesday, October 16, 2012 12:51:40 PM UTC-4, Jose wrote:
>>>>>
>>>>> I gave both a try and neither looked as it should. Method 2 displays
>>>>> the chart as it did previous where it was plotting the null '0' values.
>>>>>
>>>>> On Monday, October 15, 2012 9:38:58 PM UTC-7, asgallant wrote:
>>>>>>
>>>>>> Hmmm...I can see two ways of handling that. One results in a messy
>>>>>> DataTable, and will probably work; the other results in a cleaner
>>>>>> DataTable, but might not work.
>>>>>>
>>>>>> Method 1: change the SQL statement to this:
>>>>>> SELECT
>>>>>> PsiBar,
>>>>>> IF(id_sample = 1, prodPerct, null) AS prodPerct1,
>>>>>> IF(id_sample = 2, prodPerct, null) AS prodPerct2,
>>>>>> IF(id_sample = 3, prodPerct, null) AS prodPerct3
>>>>>> FROM tbl_dilution
>>>>>>
>>>>>> removing the sums and the group by clause. This will result in more
>>>>>> rows of data (with duplicate domain column entries) than necessary.
>>>>>>
>>>>>> Method 2: this will work only if 0 is not a valid value for your data
>>>>>> points to have. Change the SQL to this:
>>>>>>
>>>>>>
>>>>>> SELECT
>>>>>> PsiBar,
>>>>>> IF(prodPerct1 = 0, null, prodPerct1) as prodPerct1,
>>>>>> IF(prodPerct2 = 0, null, prodPerct2) as prodPerct2,
>>>>>> IF(prodPerct3 = 0, null, prodPerct3) as prodPerct3
>>>>>> FROM (
>>>>>> SELECT
>>>>>> PsiBar,
>>>>>> SUM(IF(id_sample = 1, prodPerct, null)) AS prodPerct1,
>>>>>> SUM(IF(id_sample = 2, prodPerct, null)) AS prodPerct2,
>>>>>> SUM(IF(id_sample = 3, prodPerct, null)) AS prodPerct3
>>>>>> FROM tbl_dilution
>>>>>> GROUP BY PsiBar
>>>>>> ) AS foo
>>>>>>
>>>>>> which tests to see if the sum is 0, and if it is, sets the value to
>>>>>> null instead. The DataTable will be cleaner, but it won't work if your
>>>>>> values can be 0.
>>>>>>
>>>>>> On Monday, October 15, 2012 6:45:51 PM UTC-4, Jose wrote:
>>>>>>>
>>>>>>> asgallant, you are right, I am trying to get three lines plotted for
>>>>>>> each 'id_sample'. Within each id group, there are 12 plot points.
>>>>>>> I've tried the code you provided, thanks, but it appears to also
>>>>>>> plot the null values '0' between each data point. How do I fix this?
>>>>>>>
>>>>>>> {"cols":[{"label":"PsiBar","type":"number"},{"label":"Series
>>>>>>> 1","type":"number"},{"label":"Series
>>>>>>> 2","type":"number"},{"label":"Series
>>>>>>> 3","type":"number"}],"rows":[{"c":[{"v":0.39},{"v":0.36},{"v":0},{"v":0}]},{"c":[{"v":0.5},{"v":0},{"v":0.26},{"v":0.11}]},{"c":[{"v":0.56},{"v":0.49},{"v":0.34},{"v":0}]},{"c":[{"v":0.57},{"v":0},{"v":0},{"v":0.16}]},{"c":[{"v":0.84},{"v":0.56},{"v":0.41},{"v":0.15}]},{"c":[{"v":1.01},{"v":0.62},{"v":0.42},{"v":0}]},{"c":[{"v":1.02},{"v":0},{"v":0},{"v":0.24}]},{"c":[{"v":1.3},{"v":0.66},{"v":0.49},{"v":0}]},{"c":[{"v":1.31},{"v":0},{"v":0},{"v":0.26}]},{"c":[{"v":1.45},{"v":0.66},{"v":0.5},{"v":0.27}]},{"c":[{"v":1.74},{"v":0},{"v":0.52},{"v":0}]},{"c":[{"v":1.75},{"v":0.68},{"v":0},{"v":0.28}]},{"c":[{"v":2.1},{"v":0},{"v":0},{"v":0.28}]},{"c":[{"v":2.11},{"v":0},{"v":0.52},{"v":0}]},{"c":[{"v":2.12},{"v":0.68},{"v":0},{"v":0}]},{"c":[{"v":2.57},{"v":0},{"v":0.49},{"v":0.27}]},{"c":[{"v":2.58},{"v":0.65},{"v":0},{"v":0}]},{"c":[{"v":3.07},{"v":0},{"v":0},{"v":0.25}]},{"c":[{"v":3.09},{"v":0.6},{"v":0.46},{"v":0}]},{"c":[{"v":3.56},{"v":0.56},{"v":0},{"v":0.23}]},{"c":[{"v":3.57},{"v":0},{"v":0.42},{"v":0}]},{"c":[{"v":4.23},{"v":0},{"v":0},{"v":0.21}]},{"c":[{"v":4.34},{"v":0},{"v":0.39},{"v":0}]},{"c":[{"v":4.36},{"v":0.51},{"v":0},{"v":0}]}]}
>>>>>>>
>>>>>>> Really appreciate your help on this!
>>>>>>>
>>>>>>> On Thursday, October 11, 2012 12:43:03 PM UTC-7, asgallant wrote:
>>>>>>>>
>>>>>>>> You're not charting 3 series there, you have 1 series. Looking at
>>>>>>>> your SQL table, I would guess that you want to display one series for
>>>>>>>> each
>>>>>>>> sample id, right? If so, then you need to break out the "prodPerct"
>>>>>>>> column
>>>>>>>> into 3 different columns - 1 for each series. This is probably best
>>>>>>>> achieved in SQL, maybe with a query like this:
>>>>>>>>
>>>>>>>> SELECT
>>>>>>>> PsiBar,
>>>>>>>> SUM(IF(id_sample = 1, prodPerct, null)) AS prodPerct1,
>>>>>>>> SUM(IF(id_sample = 2, prodPerct, null)) AS prodPerct2,
>>>>>>>> SUM(IF(id_sample = 3, prodPerct, null)) AS prodPerct3
>>>>>>>> FROM tbl_dilution
>>>>>>>> GROUP BY PsiBar
>>>>>>>>
>>>>>>>> and then use this to build the table:
>>>>>>>>
>>>>>>>> $table['cols'] = array(
>>>>>>>> array('label' => 'PsiBar', 'type' => 'number'),
>>>>>>>> array('label' => 'Series 1', 'type' => 'number')
>>>>>>>> array('label' => 'Series 2', 'type' => 'number')
>>>>>>>> array('label' => 'Series 3', 'type' => 'number')
>>>>>>>> );
>>>>>>>>
>>>>>>>> $rows = array();
>>>>>>>> while($r = mysql_fetch_assoc($sth)) {
>>>>>>>> $temp = array();
>>>>>>>> $temp[] = array('v' => (float) $r['psiBar']);
>>>>>>>> $temp[] = array('v' => (float) $r['prodPerct1']);
>>>>>>>> $temp[] = array('v' => (float) $r['prodPerct2']);
>>>>>>>> $temp[] = array('v' => (float) $r['prodPerct3']);
>>>>>>>> $rows[] = array('c' => $temp);
>>>>>>>> }
>>>>>>>>
>>>>>>>> On Thursday, October 11, 2012 12:50:04 PM UTC-4, Jose wrote:
>>>>>>>>>
>>>>>>>>> Hi asgallant,
>>>>>>>>>
>>>>>>>>> Seeing Diana's example, I tried doing something similar with a
>>>>>>>>> Line graph but it's not coming out as I'd like.
>>>>>>>>> It displays the three series but links them all together instead
>>>>>>>>> of individually displaying them (lineChart.jpg).
>>>>>>>>> What I'm trying to achieve, is something similar to how it's
>>>>>>>>> displayed in Excel (chart_xls.jpg).
>>>>>>>>> If you could help me in the right direction, I'd appreciate it
>>>>>>>>> alot as I have been trying various things and the outcome
>>>>>>>>> isn't what I'm expecting.
>>>>>>>>>
>>>>>>>>> José
>>>>>>>>>
>>>>>>>>> On Wednesday, September 26, 2012 10:11:01 AM UTC-7, asgallant
>>>>>>>>> wrote:
>>>>>>>>>>
>>>>>>>>>> What is throwing that error message? Is it PHP?
>>>>>>>>>>
>>>>>>>>>> You will have to adjust the data types to the type of data you
>>>>>>>>>> are using, so if your first column isn't type string, you need to
>>>>>>>>>> change it
>>>>>>>>>> to something else in the column definitions (this goes for all
>>>>>>>>>> columns -
>>>>>>>>>> types must always match). Also, the (string) typecasting in this
>>>>>>>>>> line:
>>>>>>>>>>
>>>>>>>>>> $temp[] = array('v' => (string) $r['PLACA']);
>>>>>>>>>>
>>>>>>>>>> is probably not necessary, unless you have a non-string data type
>>>>>>>>>> that you need to specifically convert into a string.
>>>>>>>>>>
>>>>>>>>>> If you can post a link to the page, I can help debug things on
>>>>>>>>>> the javascript end, if it turns out that is where the problem is.
>>>>>>>>>>
>>>>>>>>>> On Wednesday, September 26, 2012 4:47:20 AM UTC-4, Barbara Gerstl
>>>>>>>>>> wrote:
>>>>>>>>>>>
>>>>>>>>>>> That is what I did... but, when opening goochart2.html, the
>>>>>>>>>>> result is the Error-Massage "string".
>>>>>>>>>>> I think, it has something to do with the field settings of the
>>>>>>>>>>> columns. Do you have any tipps?
>>>>>>>>>>>
>>>>>>>>>>> Thank you!
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> Am Montag, 24. September 2012 19:26:26 UTC+2 schrieb asgallant:
>>>>>>>>>>>>
>>>>>>>>>>>> You can extrapolate from the code that the table has 6 columns:
>>>>>>>>>>>> PLACA, S1, S2, S3, S4, S5.
>>>>>>>>>>>>
>>>>>>>>>>>> On Monday, September 24, 2012 10:15:44 AM UTC-4, Barbara Gerstl
>>>>>>>>>>>> wrote:
>>>>>>>>>>>>>
>>>>>>>>>>>>> Hello Diana!
>>>>>>>>>>>>>
>>>>>>>>>>>>> Thank you very much for showing the whole process on how to
>>>>>>>>>>>>> combine Google Graph API with a MySQL-Database. That is exactly
>>>>>>>>>>>>> what I am
>>>>>>>>>>>>> looking for.
>>>>>>>>>>>>>
>>>>>>>>>>>>> I tried to rebuild your example and I am having problems with
>>>>>>>>>>>>> the structure of the database/field settings. Can you show me
>>>>>>>>>>>>> structure and
>>>>>>>>>>>>> field settings of the table "bd_salidas"?
>>>>>>>>>>>>>
>>>>>>>>>>>>> Thank you for your answer.
>>>>>>>>>>>>> Barbara
>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>> Am Mittwoch, 5. September 2012 21:56:35 UTC+2 schrieb Diana
>>>>>>>>>>>>> Flores:
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> yeaaaaaaahhhHHHH!!!!, we did it!!!!!!!!!!!!!. well at first i
>>>>>>>>>>>>>> tried the .DataTable(jsonData); but it gave me errors but i put
>>>>>>>>>>>>>> the
>>>>>>>>>>>>>> JSON.parse(jsonData)); and it works!!!!!!!!!!!!!!!!!!....im so
>>>>>>>>>>>>>> happy!!! i
>>>>>>>>>>>>>> will attach the files in case someone has the same
>>>>>>>>>>>>>> problem!!!!!!!!....really really grateful, cause with your help
>>>>>>>>>>>>>> i learned a
>>>>>>>>>>>>>> lot of things!!!!....one month ago I was "what its php or
>>>>>>>>>>>>>> mysql....JSON
>>>>>>>>>>>>>> O_O???" i think its a lot, but thanks!!!!
>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
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