Worked like a charm. Thanks a bunch mate for the right answer and for the 
quick response!


On Saturday, 19 January 2013 02:54:03 UTC, asgallant wrote:
>
> Try it in Chrome and look in the developer's console for error messages to 
> see what might be going on.  At a guess, I would say that record["cost"]is 
> being input as a string instead of a number (test with alert(typeof 
> rowdata[2][1]);)..
>
> On Friday, January 18, 2013 7:30:56 PM UTC-5, Andy Gan wrote:
>>
>> Hi asgallant,
>>
>> I'm having a similar issue, and I have tried your technique but failed. 
>> What's wrong here? The array looks fine, as evidenced by the testing, but 
>> for some reason it refuses to push the data. It works if I comment out the 
>> section in blue though.
>>
>> Any help would be tremendous! 
>>
>> Cheers.
>>
>> Andy
>>
>> // Create the data table.
>> var data = new google.visualization.DataTable();
>> data.addColumn('string', 'RAG');
>> data.addColumn('number', 'Cost');
>>
>> // initiates array, and tries push into it
>> var rowdata = [ ['a',1000] ];
>> rowdata.push(['b',200]);    
>> alert('2nd row ' + rowdata[1][0] + ' | '+rowdata[1][1]);        // this 
>> is OK, returns '2nd row b | 200'
>>
>> // iterate through data
>> act({id:itcap}).each(function (record,recordnumber) {
>>     alert('test 3rd row ' + record["rag"] + ' | '+record["cost"]);  // 
>> this is also ok, returns 'test 3rd row A | 60'
>>                                                                     // 
>> this proves that record["rag"] and record["cost"] is OK
>>     rowdata.push([record["rag"],record["cost"]]);
>> });
>> alert('3rd row ' + rowdata[2][0] + ' | '+rowdata[2][1]);        // this 
>> is OK, returns '3rd row A | 60' as expected
>>
>> // adds into the data table
>> data.addRows(rowdata);                                          // no 
>> data appears
>>
>>
>> On Monday, 10 December 2012 17:47:10 UTC, asgallant wrote:
>>>
>>> You are creating rowData as a string, not an array, which is why it 
>>> doesn't work.  Try this instead:
>>>
>>> var rowData = ['a', 10];
>>> for (var i=0;i<=10;i++){
>>>     c[i]= id.firstChild.getElementsByTagName('th')[i].innerHTML;
>>>     rowData.push([c[i], 10]);
>>> }
>>>
>>> On Monday, December 10, 2012 3:21:21 AM UTC-5, Logesh waran wrote:
>>>>
>>>> Hi , 
>>>> I am using a javascript function to get the row data and storing that 
>>>> in a variable called 'rowData' .
>>>> Now the value of rowData is ['CVS update Issue',10],['Testbed Issue - 
>>>> Ping Failure',10],['Testbed Issue - Software Missing',10]
>>>> But when substituted in the addRows([rowData]) it is not creating any 
>>>> chart .
>>>> But when the values is directly given without using a variable , the 
>>>> chart is produced .
>>>>
>>>> Please see my script below .Kindly help .
>>>>
>>>> <script type="text/javascript">
>>>>
>>>>       google.load('visualization', '1.0', {'packages':['corechart']});
>>>>       google.setOnLoadCallback(drawChart);
>>>>
>>>>       function drawChart() {
>>>>           var data = new google.visualization.DataTable();
>>>>
>>>>           var rowData="['a',10]";
>>>>           
>>>>           var id= document.getElementById('summary');
>>>>
>>>>           var c =  new Array();
>>>>
>>>>           for(var i=0;i<=10;i++){
>>>>               c[i]= 
>>>> id.firstChild.getElementsByTagName('th')[i].innerHTML;
>>>>               rowData="['"+c[i]+"',10]"+','+ rowData;
>>>>           }
>>>>
>>>>           
>>>>            data.addColumn('string', 'Suite');
>>>>            data.addColumn('number', 'TestCases');
>>>>            data.addRows(rowData);                                       
>>>>                              // Here is where the problem is .how can 
>>>> i handle this with a variable .
>>>>            var options = {'title':'FA','width':400,'height':300};
>>>>            var chart = new 
>>>> google.visualization.PieChart(document.getElementById('chart_div'));
>>>>            chart.draw(data, options);
>>>>       }
>>>>  </script>
>>>>
>>>

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