Can I deselect an element manually in code without requiring another click?
Because currently, the solution you offered requires 2 clicks on the same
element when the first (deselect) does nothing and the 2nd one is the
select one.
On Sunday, January 20, 2013 7:20:47 PM UTC+2, asgallant wrote:
>
> If you click on a selected element, it deselects that element, but the
> "select" event is still fired. You can test to see if anything is selected
> by checking the length of the array returned by
> table.getChart().getSelection():
>
> google.visualization.events.addListener(table, 'select', function () {
> var sel = table.getChart().getSelection();
> if (sel.length > 0) {
> var tmpData = table.getDataTable();
> var msgArray = ['You have selected:'];
> for (var i = 0; i < sel.length; i++) {
> msgArray.push(tmpData.getValue(sel[i].row, 0));
> }
> alert(msgArray.join('\n'));
> }
> });
>
> On Sunday, January 20, 2013 7:21:02 AM UTC-5, [email protected] wrote:
>>
>> There's a little bug there that I can't find. The exact code you posted..
>>
>> When you click on someone I get an alert, if I click on it on the 2nd
>> time (on the same line) it's undefined, on the 3rd time (again on the same
>> line) it's back again and so on..
>>
>> Any idea why?
>>
>> On Friday, January 11, 2013 3:44:27 PM UTC+2, [email protected] wrote:
>>>
>>> How can I add a select event to the StringFilter? (
>>> https://code.google.com/apis/ajax/playground/?type=visualization#stringfilter_control
>>> )
>>> (like it's done here:
>>> https://code.google.com/apis/ajax/playground/?type=visualization#select_eventbut
>>> for a simple table).
>>>
>>
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