thanks my friend u are right .. but everithing else looks ok.
2013/4/3 asgallant <[email protected]> > The PHP function is json_encode, not jsonencode. > > > On Wednesday, April 3, 2013 5:31:22 PM UTC-4, Chrystopher Medina wrote: > >> my friend it works perfectly thanks..... my friend i have anoter cuestion >> >> well i have a form and i send my data to the server in order to check if >> the user and passwor are ok. >> i do this jus to test. >> >> thi is my php file >> >> if($_post['user']=='xhava' && $_post['password']=='12345'){ >> echo 1; >> }else { >> echo 0; >> } >> >> and in my javascript file i jus have this >> >> well i have mi function in order to send the data to the server and in >> order to receive the values i do thi >> >> function(data){ >> if(data===1){ >> alert("you have logged"); >> }else{ >> alert("you have not logged in "); >> } >> } >> >> but how i can send from my php file to the javascript file the data in >> json format...... >> >> i had done somethin like this but it did not work. >> >> $myarray = array(); >> >> if($_post['user']=='xhava' && $_post['password']=='12345'){ >> $myarray[0] = 1; >> }else { >> $myarray[0]=0; >> } >> >> echo jsonencode($myarray); >> >> >> >> >> >> >> >> >> >> 2013/4/3 asgallant <[email protected]> >> >> Like most things, sessionstorage and server sessions have their benefits >> and drawbacks, and which you use largely depends on what you need to >> accomplish; neither one is inherently better than the other. Basically, >> the difference as I understand it is that PHP's sessions tie data to a >> particular connection to the server for the duration of the session while >> sessionstorage keeps data locally in the browser, tied to a particular tab >> and a particular domain. If you need to access the data to do things on >> the server, you probably want to use PHP's sessions; if what you want to do >> is all in javascript, then you might want to use sessionstorage. >> >> As far as the other problem you are having goes, I can't be certain of >> the cause without being able to test it. My suggestion would be to move >> any jQuery that acts on the content in secondpage.html into >> secondpage.html, and wrap it in a document.ready event handler: >> >> $(function () { >> // javascript that does things on the contents of secondpage.html >> }); >> >> >> On Wednesday, April 3, 2013 7:49:31 AM UTC-4, Chrystopher Medina wrote: >> >> my friend could you explain me something please.. look, i have my >> index.html some like this: >> <script>here is the jquery library </script> >> >> <script> >> window.addEvenListener('load',****inicia,false); >> function inicia(){ >> $("#firstbutton").on('click',**f**unction(){ >> $("content").load('secondpage.****html'); >> }); >> >> $("#secondbutton").on('click',****function(){ >> alert("i am the second button"); >> }); >> >> } >> </script> >> <div id="content">hellow world</div> >> <input type=button value=ok id=firstbutton> >> >> and then i have another file html named secondpage.html >> this file has something like this: >> >> <div>this is the second page</div> >> <input type=button value=ok id=secondbutton> >> >> well, i have my javascript file just in the first page(index.html) and >> when i click in the button id=firstbutton, the second page named >> secondpage.html is loaded inside my index.html in the div with >> id=content.. until here everything works fine..but >> but when I click on the second button in my second page does not show me >> the alert("i am the second button") >> >> I thought I just had to include the jQuery library and the script >> javascript in my index.html and as the second page is being loaded into my >> index.html, this second page could run the scripts included in my index. >> >> i hope u can explain me this. >> >> >> >> >> >> >> >> 2013/4/3 Chrystopher Medina <[email protected]> >> >> could you gime some diferences between both of them >> >> >> >> 2013/4/3 Chrystopher Medina <[email protected]> >> >> my friend u think that is better that i use sessionstorage from html5 or >> sesions with php >> >> >> 2013/4/2 asgallant <[email protected]> >> >> The first two header lines tell IE not to cache the results (you may or >> may not want to include them, depending on whether you want caching enabled >> or not). The last one helps the browser interpret the data, and looks >> correct if you are returning a JSON string. >> >> >> On Tuesday, April 2, 2013 4:05:56 AM UTC-4, Chrystopher Medina wrote: >> >> mi friend could you explain me this again please. >> >> header('Cache-Control: no-cache, must-revalidate'); >> header('Expires: Mon, 26 Jul 1997 05:00:00 GMT'); >> header('Content-type: application/json');// well this is to tell to the >> script that json is the type of data that im gonna send ... am i ok ? >> >> because i´ve forgot it ... about jquery with ajax i´ve been studing a lot >> , and i think that i´m learning a lot abount that. >> >> >> 2013/3/27 Chrystopher Medina <[email protected]> >> >> >> please my friend. for example.... >> >> this is a button ... and when i click on it .... i want to >> go to the php script, and obtain values from my database... then i want to >> <div id="values"></div> send the values to the div with id=values >> >> >> -- >> You received this message because you are subscribed to a topic in the >> Google Groups "Google Visualization API" group. >> To unsubscribe from this topic, visit https://groups.google.com/d/**to** >> pic/google-visualization-**api/-**zapZe7dH7Y/unsubscribe?**hl=en<https://groups.google.com/d/topic/google-visualization-api/-zapZe7dH7Y/unsubscribe?hl=en> >> . >> To unsubscribe from this group and all its topics, send an email to >> google-visualization-api+**unsub**[email protected]. >> To post to this group, send email to google-visua...@**googlegroups.**com >> . >> >> Visit this group at <a href="http://groups.google.**com/group/google-** >> visualization-api?hl<http://groups.google.com/group/google-visualization-api?hl> >> >> ... > > -- > You received this message because you are subscribed to a topic in the > Google Groups "Google Visualization API" group. > To unsubscribe from this topic, visit > https://groups.google.com/d/topic/google-visualization-api/-zapZe7dH7Y/unsubscribe?hl=en > . > To unsubscribe from this group and all its topics, send an email to > [email protected]. > To post to this group, send email to > [email protected]. > Visit this group at > http://groups.google.com/group/google-visualization-api?hl=en. > For more options, visit https://groups.google.com/groups/opt_out. > > > -- You received this message because you are subscribed to the Google Groups "Google Visualization API" group. 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