Mi ingles es muy malo.
Gracias por la atención, asgallant.
Quiero crear un grafico de intersecciones. Lo he logrado. Ahora la idea es
dividir en 2. Con un color en base a un campo de la tabla y con otro color en
base a ese mismo campo.
Ejemplo.
> var data = new google.visualization.DataTable();
> data.addColumn('number', 'coox');
> data.addColumn('number', 'cooy');
> data.addColumn({type:'string', role:'tooltip',
> 'jugador': {'html': true}}); // tooltip for first series
agregar,
data.addColumn(’string’,’alianza’);
Datos de la Tabla
Si alianza = ‘alianza’ uso color Rojo y si no uso color Azul.
Dividir en 2 grupos el grafico.
Logras entender?
Muchisimas gracias!!
El 02/11/2013, a las 12:12, asgallant <[email protected]> escribió:
> I'm sorry, but I don't understand your questions. If you ask the questions
> in your native language, I can try to have them translated.
>
> On Friday, November 1, 2013 11:29:00 PM UTC-4, Santiago Fernandez wrote:
> Dear,
>
> I'm not a developer. Then, a lot of effort to achieve graph a Scratter with
> the following code.
>
> This One...
>
> <script type="text/javascript">
> google.load("visualization", "1", {packages:["corechart"]});
> google.setOnLoadCallback(drawChart);
> function drawChart() {
> var data = new google.visualization.DataTable();
> data.addColumn('number', 'coox');
> data.addColumn('number', 'cooy');
> data.addColumn({type:'string', role:'tooltip',
> 'jugador': {'html': true}}); // tooltip for first series
> <?php
> $listar_grafico = mysql_query("SELECT * FROM
> jugadores");
> while ($row = mysql_fetch_array($listar_grafico)) {
> ?>
> data.addRow([<?=$row['coox']?>,
> <?=$row['cooy']?>, '<?=$row['jugador']?>']);
> <?
> }
> mysql_free_result($listar_grafico);
> ?>
> var options = {
> title: 'Mapa de Alianza',
> hAxis: {title: 'Eje X', minValue: 0, maxValue:
> 1020},
> vAxis: {title: 'Eje Y', minValue: 0, maxValue:
> 1020},
> pointSize:4,
> legend: 'none'
> };
> var chart = new
> google.visualization.ScatterChart(document.getElementById('chart_div'));
> chart.draw(data, options);
> }
> </script>
>
> I have some form of cross-checking with another?
>
> Or failing and add one more and with an IF color to the two groups of the
> same DataTable?
>
> Do you under stand me?
>
> Thanks!!
>
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