Nothing sticks out at me immediately.  Open the page in a browser, view the 
source, and post it here.  I want to see what your PHP is rendering as 
javascript.

On Sunday, November 10, 2013 1:00:48 PM UTC-5, Atik Bayraktar wrote:
>
> Guys, Ive been working on that too.. I got my datas from database and send 
> them to chart but I see a blank page when I try it in WAMP... no errors but 
> there is not something to see.
>
> code:
>
>
>
> <html>
>   <head>
>     <script type="text/javascript" src="
> https://www.google.com/jsapi";></script>
>     <script type="text/javascript">
>       google.load("visualization", "1", {packages:["corechart"]});
>       google.setOnLoadCallback(drawChart);
>       function drawChart() {
>         var data = google.visualization.arrayToDataTable([
>         
> <?php
>
>
> $con = mysql_connect("localhost:3306", "reverse", "");
>
> if (!$con) {
>     die('Could not connect: ' . mysql_error());
> }
>
> mysql_select_db($database, $con);
> $result = mysql_query("SELECT * FROM `test` LIMIT 0 , 30");
>
> $output = array();
> while($row = mysql_fetch_array($result)) {
>     // create a temp array to hold the data
>     $temp = array();
>      
>     // add the data
>     $temp[] = '"' . $row['Temp'] . '"';
>     $temp[] = '"' . $row['Humidity'] . '"';
>     $temp[] = '"' . $row['Light'] . '"';
>
>     // implode the temp array into a comma-separated list and add to the 
> output array
>     $output[] = '[' . implode(', ', $temp) . ']';
> }
> // implode the output into a comma-newline separated list and echo
> echo implode(",\n", $output);
> mysql_close($con);
> ?>        
>     
>         ]);
>         var options = {
>           title: 'Selfcheck Stats'
>         };
>         var chart = new 
> google.visualization.LineChart(document.getElementById('chart_div'));
>         chart.draw(data, options);
>       }
>     </script>
>   </head>
>   <body>
>     <div id="chart_div" style="width: 900px; height: 500px;"></div>
>   </body>
> </html>
>
>
> ---
>
>
> Please help ;)
>

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