It works...! Thank you.
On Monday, December 16, 2013 8:25:18 PM UTC+5:30, asgallant wrote:
>
> You have to change a few things in your code. First, the viewColumnsneeds to
> contain both columns 0 and 1 to start if you want
> Column1 and Column2 to both be in the output. Then, you need to adjust
> the columns you add to the viewColumns: each one needs a calc parameter
> which calculates the value in the column. In this case, you want to
> compare the value of the column to distinctValues[i] and return 1 when
> they match and 0 when they don't. In the aggregation function for
> groupColumns, use sum instead of count:
>
> var distinctValues = data.getDistinctValues(2);
>
> var viewColumns = [0, 1];
> var groupColumns = [];
> // build column arrays for the view and grouping
> for (var i = 0; i < distinctValues.length; i++) {
> viewColumns.push({
> type: 'number',
> label: distinctValues[i],
> calc: (function (x) {
> return function (dt, row) {
> return (dt.getValue(row, 2) == x) ? 1 : 0;
> }
> })(distinctValues[i])
> });
> groupColumns.push({
> column: i+2,
> type: 'number',
> //label: distinctValues[i],
> aggregation: google.visualization.data.sum
> });
> }
>
> Then, in the grouping function, pass columns 0 and 1 in the first array:
>
> var pivotedData = google.visualization.data.group(view, [0, 1],
> groupColumns);
>
> See these changes working here: http://jsfiddle.net/asgallant/DUn6B/1/
>
> On Monday, December 16, 2013 1:02:35 AM UTC-5, Pradeep Shankar M wrote:
>>
>> I excited with this fiddle <http://jsfiddle.net/asgallant/HkjDe/> and I
>> tried to create the same kind with reference to that fiddle. My modified
>> sample is given in here <http://jsfiddle.net/DUn6B/> and i'm trying to
>> create a view as follows.
>>
>> var distinctValues = data.getDistinctValues(2);
>>
>> var viewColumns = [1];
>> var groupColumns = [];
>> // build column arrays for the view and grouping
>> for (var i = 0; i < distinctValues.length; i++) {
>> viewColumns.push({
>> type: 'number',
>> label: distinctValues[i],
>> aggregation: google.visualization.data.count
>> });
>> groupColumns.push({
>> column: i+1,
>> type: 'number',
>> //label: distinctValues[i],
>> aggregation: google.visualization.data.sum
>> });
>> }
>>
>> But my aim is to create a pivot table something like as follows.
>>
>> ['Column1', 'Column2', 100, 200, 300, 400],['A', 'bar', 0, 1, 1, 0],['A',
>> 'baz', 0, 0, 1, 0],['A', 'foo', 3, 1, 0, 0],['B', 'baz', 0, 1, 0, 0],['B',
>> 'cad', 1, 0, 1, 1],['B', 'qud', 1, 1, 1, 2]
>>
>> How can I proceed?
>>
>
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