This is likely not working because taking the responseText from the AJAX
call gives a string, not an array:
var jsonData = $.ajax({
url: "getData.php",
dataType:"json",
async: false
}).responseText;
// jsonData = '[["Datum","Temperatur"],["2014-02-11
12:42:55",21.9],["2014-02-11 12:42:55",21.9],...]';
You need to parse the JSON string before passing it to the arrayToDataTable
method:
var data = new google.visualization.DataTable(JSON.parse(jsonData));
On Friday, February 14, 2014 12:20:43 PM UTC-5, Benedikt Peichel wrote:
>
> Hi
>
> i have connected a mysql db to line chart but it doesn' work: the
> following code i use
>
> <html>
> <head>
> <script type="text/javascript" src="https://www.google.com/jsapi
> "></script>
> <script type="text/javascript" src="//
> ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
> <script type="text/javascript">
> google.load("visualization", "1", {packages:["corechart"]});
>
> google.setOnLoadCallback(drawChart);
>
> function drawChart() {
>
> var jsonData = $.ajax({
> url: "getData.php",
> dataType:"json",
> async: false
> }).responseText;
> var data = new google.visualization.DataTable(jsonData);
>
> var options = {
> title: 'Company Performance',
> curveType: 'function'
> };
>
> var chart = new
> google.visualization.LineChart(document.getElementById('chart_div'));
> chart.draw(data, options);
> }
> </script>
> </head>
> <body>
> <div id="chart_div" style="width: 900px; height: 500px;">Test</div>
> </body>
> </html>
>
>
> <?php
>
> //in der DB suchen
> function getdb($SQL_statement){
> $conn_host="localhost";
> $conn_userid="root";
> $conn_passwd="admin";
> $conn_db="temperaturverlauf";
> $db_conn = mysql_connect($conn_host,$conn_userid,$conn_passwd) or die
> ("Verbindung fehlgeschlagen ".mysql_error());
> mysql_select_db($conn_db,$db_conn);
> $resultset=mysql_query($SQL_statement);
> return $resultset;
> mysql_close();
> }
>
>
> //Letzte 24 Stunden
> $sqlst=getdb("SELECT * FROM asdf LIMIT 0, 30;");
>
> //echo "Daten gelesen";
> $daten = array();
> $daten[0] = array('Datum', 'Temperatur');
> $i = 1;
>
> while($data=mysql_fetch_array($sqlst)){
> $daten[$i] = array($data['datum'], (double) $data['t0']);
> $i = $i + 1;
> }
> $json = json_encode($daten);
> echo $json;
> ?>
>
>
> the php output is:
>
> [["Datum","Temperatur"],["2014-02-11 12:42:55",21.9],["2014-02-11
> 12:42:55",21.9],["2014-02-11 12:42:55",21.8],["2014-02-11
> 12:42:55",21.7],["2014-02-11 12:42:55",21.7],["2014-02-11
> 12:42:55",21.6],["2014-02-11 12:42:55",21.6],["2014-02-11
> 12:42:55",21.5],["2014-02-11 12:42:55",21.4],["2014-02-11
> 12:42:55",21.4],["2014-02-11 12:42:55",21.3],["2014-02-11
> 12:42:55",21.2],["2014-02-11 12:42:55",21.2],["2014-02-11
> 12:42:55",21.1],["2014-02-11 12:42:55",21.1],["2014-02-11
> 12:42:55",21],["2014-02-11 12:42:55",20.9],["2014-02-11
> 12:42:55",20.9],["2014-02-11 12:42:55",20.8],["2014-02-11
> 12:42:55",20.7],["2014-02-11 12:42:55",20.7],["2014-02-11
> 12:42:55",20.6],["2014-02-11 12:42:55",20.6],["2014-02-11
> 12:42:55",20.5],["2014-02-11 12:42:55",20.4],["2014-02-11
> 12:42:55",20.4],["2014-02-11 12:42:55",20.3],["2014-02-11
> 12:42:55",20.2],["2014-02-11 12:42:55",20.2],["2014-02-11 12:42:55",20.1]]
>
>
>
> an the output is table has no data, what is wrong?
>
> thank's!!
>
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