This is the full function. The website can find up to
url: "getData.php",
It isn't showing any more errors. What is the easiest way to see
exactly is being returned by the ajax call?
<!--Load the AJAX API--> <script type="text/javascript"
src="https://www.google.com/jsapi
<view-source:https://www.google.com/jsapi>"></script> <script
type="text/javascript"
src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js
<view-source:http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js>"></script>
<script type="text/javascript"> google.load('visualization',
'1', {'packages': ['geochart']});
google.setOnLoadCallback(drawMarkersMap);function drawMarkersMap() {
$.ajax({ url: "getData.php", dataType:"json",
success: function (json) { // Create our data table
out of JSON data loaded from server.var data = new
google.visualization.arrayToDataTable(JSON.parse(json)); //
var data = new google.visualization.DataTable(json); var
options = { region: 'US', displayMode:
'markers', colorAxis: {colors: ['green', 'blue']}
}; var chart = new
google.visualization.GeoChart(document.getElementById('visualization'));
chart.draw(data, options); } // <-- the ";" that was
here does not belong }); // <-- missing this} // <-- and
this</script>
On Thu, Mar 6, 2014 at 2:07 PM, asgallant <[email protected]> wrote:
> That sounds like a variable scope problem, and is likely due to having the
> chart.draw call in the wrong place. Post the code you are using that
> causes the problem.
>
>
> On Thursday, March 6, 2014 1:49:54 PM UTC-5, Timothy Sheils wrote:
>
>> Ok. got that fixed. I looked at the developer console in firefox. I'm
>> getting an error: ReferenceError: data is not defined for the line
>>
>> chart.draw(data, options);
>>
>> It feels like something isn't right with the ajax call.
>>
>>
>> On Thu, Mar 6, 2014 at 1:33 PM, asgallant <[email protected]> wrote:
>>
>>> There is another thing you need to change. On this line:
>>>
>>> var data = new google.visualization.DataTable(jsonData);
>>>
>>> change "jsonData" to "json":
>>>
>>> var data = new google.visualization.DataTable(json);
>>>
>>> You not not need to assign the AJAX call to a variable.
>>>
>>> On Thursday, March 6, 2014 12:12:12 PM UTC-5, Timothy Sheils wrote:
>>>>
>>>> That didn't help. I have been following a previous post you were
>>>> working on: https://groups.google.com/forum/#!topic/google-
>>>> visualization-api/CUI5M90NTvU
>>>>
>>>> Should i set the ajax call to a variable:
>>>> " $.ajax({"
>>>> or
>>>>
>>>> "var ajaxData =
>>>> $.ajax({"
>>>> var data = new google.visualization.DataTable(ajaxData);
>>>>
>>>>
>>>> I'm also worried the json string might not be in the right format, i
>>>> tested it, and its valid, but not going through.
>>>>
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