No.  If you put the javascript in a separate file, the PHP code would not 
work.

On Wednesday, July 9, 2014 11:17:28 AM UTC-4, khalil negron wrote:
>
> is the script part suppose to go into a different file ?
>
> On Monday, July 7, 2014 2:12:25 PM UTC-4, khalil negron wrote:
>>
>> Trying to turn this data retrieved from mysql database into a chart or 
>> graph. 
>> Here my code queries the database and displays it as a table, i want to 
>> also display it as a chart underneath the table. I have read all the google 
>> doc information still can not grasp this. Can someone help.
>>
>> Thanks
>>
>> <?php
>>
>> //formula for toner usage total pages/35000 = #toner used for month
>>
>> if(isset($_POST["YEAR"])) { 
>>     $year = $_POST['YEAR'];
>>  $result = mysqli_query($dbhandle,"SELECT `Servers`, `Total Pages` / 
>> 35000 FROM summaryofserver WHERE 
>> RIGHT(Servers,4) = '$year'");
>> $result2 = mysqli_query($dbhandle, "SELECT SUM(`Total Pages` / 35000) 
>> FROM summaryofserver WHERE 
>> RIGHT(Servers,4) = '$year'");
>>  echo "<table border='1'>
>> <tr>
>> <th>Server, Month, Year</th>
>> <th>Number of Toner Cartridges Used</th>
>> </tr>";
>>  while($row = mysqli_fetch_array($result)) {
>> echo "<tr>";
>> echo "<td>" . $row[0] . "</td>";
>> echo "<td>" . $row[1] . "</td>";
>> echo "</tr>";
>> }
>> $sum = mysqli_fetch_array($result2);
>> echo "<tr>";
>> echo "<td>" .'Total for Year:'. $year. "</td>";
>> echo "<td>" . $sum[0] . "</td>";
>> echo "</tr>";
>> echo "</table>";
>> } 
>> ?>
>>
>

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