Hi Manuel,

I wasn't able to reproduce your issue, but here is a jsfiddle that has the
code you wrote: http://jsfiddle.net/o4banc3z/

I hope that helps.

On Tue Oct 28 2014 at 1:36:07 PM Manuel <[email protected]> wrote:

> Hi,
>
> I just started with the google visualization API (actually with the whole
> html/php etc. thing :-) ).
> So what I've got right now is the following PHP:
>
> <!-- Datei zum bereitstellen von Daten für GEO-CHART -->
>
> <?php
>         $MYSQL_HOST="localhost";
>         $MYSQL_BENUTZER="root";
>         $MYSQL_KENNWORT="" ;
>         $MYSQL_DATENBANK="db_index";
>
>
>     $db =  mysql_connect($MYSQL_HOST, $MYSQL_BENUTZER, $MYSQL_KENNWORT)or die 
> (mysql_error ());
>     mysql_select_db($MYSQL_DATENBANK) or die(mysql_error());
>
>     $year = '2014';
>
>     $SQLString = "SELECT 
> tb_countries.label,datenpool.id,datenpool.jahr,datenpool.dblindex
>                                         FROM ( SELECT ID,Jahr,dblIndex FROM 
> tb_ind_fra
>                                 UNION
>                                 SELECT ID,Jahr,dblIndex FROM tb_ind_ger
>                                 ) datenpool
>                     INNER JOIN tb_countries
>                     ON tb_countries.ID = datenpool.ID
>                                         WHERE datenpool.jahr = '$year'";
>
>     $result = mysql_query($SQLString);
> # build Google API JSON for GEO CHART
>         # Columns
>         echo "{ \"cols\": [ 
> {\"id\":\"\",\"label\":\"Country\",\"type\":\"string\"}, 
> {\"id\":\"\",\"label\":\"Index\",\"type\":\"number\"} ], \"rows\": [ ";
>         # Rows
>         $total_rows = mysql_num_rows($result);
>         $row_num = 0;
>         while($row = mysql_fetch_array($result)){
>     $row_num++;
>     if ($row_num == $total_rows){
>       echo "{\"c\":[{\"v\":\"" . $row['label'] . "\",\"f\":null},{\"v\":" . 
> $row['dblindex'] . ",\"f\":null}]}";
>     } else {
>       echo "{\"c\":[{\"v\":\"" . $row['label'] . "\",\"f\":null},{\"v\":" . 
> $row['dblindex'] . ",\"f\":null}]}, ";
>     }
>   }
>   echo " ] }";
>
>     mysql_close($db);
> ?>
>
>
> When I call this file I get:
> { "cols": [ {"id":"","label":"Country","type":"string"}, {"id":"","label":
> "Index","type":"number"} ], "rows": [ {"c":[{"v":"Germany","f":null},{"v":
> 300,"f":null}]}, {"c":[{"v":"France","f":null},{"v":150,"f":null}]} ] }
>
> And then I try to create the geochart with this:
> <html>
>   <head>
>      <!--Load the AJAX API-->
>   <script type="text/javascript" src="http://www.google.com/jsapi
> "></script>
>  <script src="//code.jquery.com/jquery-1.11.0.min.js"></script>
> <script src="//code.jquery.com/jquery-migrate-1.2.1.min.js"></script>
>   <script type="text/javascript">
>       google.load("visualization", "1", {packages:["geochart"]});
>       google.setOnLoadCallback(drawRegionsMap);
>
>       function drawRegionsMap() {
>
>         var jsonData = $.ajax({
>           url: "geo.php",
>           dataType:"json",
>           async: false
>           }).responseText;
>
>       // Create our data table out of JSON data loaded from server.
>       var data = new google.visualization.DataTable(jsonData);
>
>
>         var options = {};
>
>         var chart = new
> google.visualization.GeoChart(document.getElementById('regions_div'));
>
>         chart.draw(data, options);
>       }
>     </script>
>   </head>
>   <body>
>     <div id="regions_div" style="width: 900px; height: 500px;"></div>
>   </body>
> </html>
>
> But ist just doesn't work. I tried several other codes but it just
> displays nothing.
> What I get is an error message: Uncaught TypeError: undefined is not a
> function
> here:
> var jsonData = $.ajax({
>
> What is wrong with my code?
>
> I'm looking forward to every feedback I get.
>
> Thank you in advance
>
> Best,
> Manuel
>
>
>
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