Hi Daniel.
I've thought at this way indeed.
I've already used JSON.parse(json); but unfortunately it doesn't work.
I don't understand what's wrong here.
One side, the content of json is good. (copy past)
On the other side, the same variable with same content doesn't works.
It's crazy.
*/Franck Danard/*
Le 29/01/2017 à 03:45, 'Daniel LaLiberte' via Google Visualization API a
écrit :
There is nothing special about the name of the variable. The issue is
what's in the variable. JSON format is actually a string that
contains a structure. It looks like you have a string as shown in
your message output, so then you will have to convert the string to a
JavaScript object by parsing it.
Here is documentation on the JavaScript JSON.parse() function:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/parse
We should try to make this all this clearer in the Google Charts
documentation.
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