Hi,

To actually send the document:

try {
        rb.send();
        }
        catch (Exception e) {
                throw new Exception(e);
        }

Again,  the above assumes a CGI environment, not Java RPC. You'll need
machinery to handle the asynchronously handle the POST response. See
the GWT docs.

-30-

On Aug 27, 1:30 pm, jchimene <[EMAIL PROTECTED]> wrote:
> Hi,
>
> The following assumes regular CGI usage. If you're using Java RPC,
> you'll use a different technique.
>
> First, you're going to parse the source document via
> XMParser.parse().
> Document docQuestionnaire = XMLParser.parse(xmlData);
>
> You may have more machinery around the above call whose purpose is to
> put an XML string into a variable. See the examples in the GWT docs.
>
> I don't address modifying the source document in this post.
>
> To send the result, simply use the modified .parse() result:
>                 RequestBuilder rb = new RequestBuilder(RequestBuilder.POST,
> URL.encode(theHost));
>                 rb.setRequestData(docQuestionnaire.toString());
>                 rb.setHeader("Content-Length",
> String.valueOf(docQuestionnaire.toString().length()));
> Again, you will have more machinery around the above code.
>
> -30-
>
> On Aug 27, 8:26 am, max_gtbd <[EMAIL PROTECTED]> wrote:
>
> > Hi,
> > I'm writing a web app to modify an xml document.
> > the document is first loaded from a server.
> > then the modified document has to be sent back to the server.
>
> > I can't find a way to send the document back.
>
> > thx if you can help.
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