The following code was 'hand extracted and modified" from a project I
am working on. Therefore there maybe typos.
There are also references / usages of classes not shown here, but you
do not need them.
The basic flow is:
1. In your class which implements "EntryPoint" create an instance of a
Logon panel class (of your own design) --- here mine is called
"MyLogonPanel"
2. Pass a reference to the Entry Point class ("this") to the Logon
Panel class --- so that later you can call back into this class
2. Add the logon panel to the "RootPanel"
3. In the constructor of the Logon Panel - create the necessary UI
components to display a logon message and places to enter UserId and
password.
4. Call your server code to verify the UserId and Password --- onSucess
() should call back a method in the Entry Point class
--- (here "loggedOn() ) which then removes the Logon Panel from
the Root Panel and replaces it with the main application screen.
I hope this helps.
Regards,
Ken.
==============================================================================================================
MyEntryPoint.java :
public class MyEntryPoint implements EntryPoint
{
MyMainScreen screen;
MyLogonPanel logon;
public void onModuleLoad()
{
logon = new MyLogonPanel(this);
RootPanel.get().add(logon);
}
public void loggedOn(MyLogonResult result)
{
RootPanel.get().remove(logon);
screen = new MyMainScreen(result);
RootPanel.get().add(screen);
}
}
========================================================================================================
MyLogonPanel.java:
public final class MyLogonPanel extends VerticalPanel
{
final TextBox userIdTB = new TextBox();
final PasswordTextBox passwordTB = new PasswordTextBox();
final Label message = new Label("Please enter userid and
password");
final MyEntryPoint entryPoint;
final VerticalPanel logonBox;
MyLogonPanel(MyEntryPoint entryPoint)
{
this.entryPoint = entryPoint;
HorizontalPanel hp1 = new HorizontalPanel();
HorizontalPanel hp2 = new HorizontalPanel();
this.add(message);
hp1.add(new Label("UserId:"));
hp1.add(userIdTB);
hp2.add(new Label("Password:"));
hp2.add(passwordTB);
this.add(hp1);
this.add(hp2);
Button logonB = new Button("Logon");
logonB.addClickListener(new LogonClickListener());
this.add(logonB);
logonBox = this;
}
private class LogonClickListener implements ClickListener
{
public void onClick(Widget sender)
{
message.setText("--trying to logon--");
MyRemoteServiceAsync call = MyRemoteService.App.getInstance
();
UserId userId = new UserId(userIdTB.getText());
PassWord password = new PassWord(passwordTB.getText());
LogonCredentials logonCredentials = new LogonCredentials
(userId, password);
call.logon(logonCredentials, new LogonCallback());
}
}
private class LogonCallback implements AsyncCallback
{
public void onFailure(Throwable caught)
{
logonBox.add(new Label("failure of LOGON callback"));
logonBox.add(new Label(caught.toString()));
logonBox.add(new Label("------END------------------"));
}
public void onSuccess(Object obj)
{
System.out.println("LOGON callback - onSuccess");
MyLogonResult result = (MyLogonResult) obj;
if (result.logonFailed())
{
message.setText(result.getResponseString());
return;
}
entryPoint.loggedOn(result);
}
}
}
*******************************************************************************************************************************************************
On Nov 24, 4:56 am, rajasekhar <[EMAIL PROTECTED]> wrote:
> I need to redirect to home page.because the problem without
> redirecting is when I refresh the home page it is going to login page
> again .Please let me know how to handle this.
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