perfect! thanks Manuel!
common-fileupload is great!
On Jul 18, 8:51 am, Manuel Carrasco <[email protected]>
wrote:
> filename = item.getName();
>
> On Sat, Jul 18, 2009 at 12:27 AM, twittwit <[email protected]> wrote:
>
> > ok thank you. i found the answer:
>
> > public class MyFormHandler extends HttpServlet{
> >    public void doPost(HttpServletRequest request, HttpServletResponse
> > response)  throws ServletException, IOException {
> >        ServletFileUpload upload = new ServletFileUpload();
>
> >        try{
> >            FileItemIterator iter = upload.getItemIterator(request);
>
> >            while (iter.hasNext()) {
> >                FileItemStream item = iter.next();
>
> >                String name = item.getFieldName();
> >                InputStream stream = item.openStream();
>
> >                // Process the input stream
> >                FileOutputStream out = new FileOutputStream
> > ("example.csv");
> >                //ByteArrayOutputStream out = new ByteArrayOutputStream
> > ();
> >                int len;
> >                byte[] buffer = new byte[8192];
> >                while ((len = stream.read(buffer, 0, buffer.length)) !
> > = -1) {
> >                    out.write(buffer, 0, len);
> >                }
> > //.......
>
> >            }
> >        }
> >        catch(Exception e){
> >            e.printStackTrace();
> >        }
>
> >    }
>
> > }
>
> > however, how can i extract the name of the csv file(client side) so
> > that the csv file in my server can have the same name?
> > thanks!!
>
> > On Jul 18, 12:19 am, Manuel Carrasco <[email protected]>
> > wrote:
> > > In the dialog between the browser and the server, the client sends a
> > > multipart/form-data request and there is more information besides the
> > file
> > > content, like form elements values, boundary tags, etc.
>
> > > I recommend you to use apache commons-fileupload library to handle
> > > multipart/form-data request in your servlets.
>
> > > On Fri, Jul 17, 2009 at 11:44 PM, imgnik <[email protected]> wrote:
>
> > > > hi all,
>
> > > > i posted a question about fileupload here
>
> > > >http://groups.google.com/group/Google-Web-Toolkit/browse_thread/threa.
> > ..
> > > > but i think i didn't phrase my question correctly. so gonna do another
> > > > attempt.
>
> > > > I tried to use a gwt fileupload widget to send a csv file to the
> > > > server. and at the server i will write it as a file (for other usage)
> > > > it by doing : (where request is the httpservletrequest and bw is the
> > > > bufferedwriter)
>
> > > >  BufferedReader r = request.getReader();
> > > >          while((thisread= r.readLine())!=null){
>
> > > >                  bw.write(thisread);
>
> > > >          }
> > > >      bw.close();
> > > >          }
> > > >          catch(Exception e1){}
>
> > > > however, i realised that the csv file send out contains :
>
> > > > ------WebKitFormBoundaryN8Z6DOy7DqEWTwtLContent-Disposition: form-
> > > > data; name="uploadFormElement"; filename="first.csv"Content-Type:
> > > > application/octet-streamBank
>
> > > > which results in the file created not the same as the file upload.
> > > > I might be wrong in my analysis. can someone advice me?
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