here is how my onSuccess function looks, in this example I'm simply
wanting to update a label's text during each loop iteration. How
would this look like using the incremental command class? Would
everything here go inside the incrementalcommand? Thanks!
public void onSuccess(MarkerDataSet<MarkerData> markerData) {
if (markerData != null) {
String numMarkers =
Integer.toString(markerData.size());
int counter = 0;
lblProgress.setText("0 out of " +
numMarkers);
pathset.getMapWrapper().setAllMarkers(markerData);
for (Iterator<MarkerData> iter =
markerData.iterator();
iter.hasNext();) {
counter++;
lblProgress.setText(Integer.toString(counter) + " out of " +
numMarkers); // this is the label I want to update
MarkerData data = iter.next();
genericMarker.add(new
SoundMarker(pathset.getMap(),data, true));
}
}
}
On Dec 2, 4:30 pm, Eric <[email protected]> wrote:
> On Dec 2, 3:25 pm, Stephen <[email protected]> wrote:> Hi,
>
> > I'm making an async callback and in the onSuccess function I loop
> > through a result set. I would like to update a label or progressbar
> > after each iteration of the loop.
>
> Use the IncrementalCommand class. In your onSuccess method, take
> the loop you were writing and place it in a command:
>
> new AsyncCallback<ArrayList<String>>() {
> public void onFailure(final Throwable t){..}
> public void onSuccess(final ArrayList<String> list) {
> final int size = list.size();
> progressBar.setCount(size); // Defined by you.
> DeferredCommand.addCommand(new IncrementalCommand() {
> private int index = 0;
> public boolean execute() {
> handle(list.get(index++)); // Defined by you.
> progressBar.progress();
> return index < size;
> }
> }
>
> }
>
> > Thanks,
> > Stephen
>
> After each element in the list is handled, the progress bar is
> updated,
> and the command is paused, to resume in a millisecond if there are
> still
> items to handle. This also prevents the browser from thinking that
> your
> application is in an indefinite loop and giving the user the chance to
> abort it.
>
> Take a progress bar from any convenient source.
>
> Respectfully,
> Eric Jablow
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