In my JPA Entity class I have:
@Entity
public class Booking {
@Id
@SequenceGenerator(name = "BOOKING", allocationSize = 1)
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator =
"BOOKING")
private Integer id;
@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinColumn(nullable = false)
private User user;
// ...
}
In my GWT View I have:
MainRequestFactory.BookingRequest bookingRequest =
reqFactory.bookingRequest();
BookingProxy bookingProxy =
bookingRequest.create(BookingProxy.class);
UserProxy userProxy = bookingRequest.create(UserProxy.class);
userProxy.setId(12);
bookingProxy.setUser(userProxy);
Request<Void> persistRequest =
bookingRequest.persist().using(bookingProxy);
persistRequest.fire(new Receiver<Void>() {
@Override
public void onSuccess(Void response) {
GWT.log("persisted");
}
});
/////////////////////
Users and Bookings persistence without the User Constraint works fine.
But with the above code I want/have to assign the user with the ID
"12" to a newly created booking. But I cannot assign a new booking to
an already existing user ID 12. I get the following error:
[EL Warning]: 2011-07-05 18:48:45.464--UnitOfWork(267787945)--
Exception [EclipseLink-4002] (Eclipse Persistence Services -
2.3.0.v20110604-r9504):
org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: org.firebirdsql.jdbc.FBSQLException: GDS
Exception. 335544665. violation of PRIMARY or UNIQUE KEY constraint
"INTEG_388" on table "USERS2"
It's because an user with the ID "12" already exists and JPA wants to
create a new user with the same ID instead of just creating a new
booking with the user ID "12" as its foreign key.
How can I tell RequestFactory NOT to create a new user but instead
just to assign the user ID of an already existing user to a new
booking entry?
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