Thanks for your help!
Seems that there isn't a general solution to this...
(Nice tip on checking exist(), I pulled my hair out a few times when I
forgot to create the folders!)
On Thursday, April 5, 2012 2:35:59 AM UTC+8, Matias Costa wrote:
>
> In web.xml:
>
> <servlet>
> <servlet-name>imageReceiver</servlet-name>
> <servlet-class>xxx.ImageReceiver</servlet-class>
>
> <init-param>
> <param-name>imagePath</param-name>
> <param-value>/the/place</param-value><!-- or C:\the\place -->
> </init-param>
> </servlet>
>
> And in the servlet:
>
> public void init(ServletConfig servletConfig) throws ServletException{
> imagePath = servletConfig.getInitParameter("imagePath");
> if (!imagePath.endsWith(File.separator)) imagePath += File.separator
> try {
> File imageFolder = new File(imagePath);
> if (!File.exists()) Util.mkdirRecursive(imagePath);
> } catch ... whatever you want to do if something fails
> }
>
> El martes 3 de abril de 2012 03:21:06 UTC+2, Sam W escribió:
>>
>> Hello,
>>
>> I haven't been able to figure this out after spending 3 hours on
>> Google.
>>
>> I can fetch an image, but I don't know where to put them.
>> If I just use "new File("image.jpg")", it will end up in my tomcat
>> bin/ folder.
>>
>> Some sugggests to use getServletContext().getRealPath("/"); but it
>> would block forever at "getServletContext", I don't know why.
>>
>> What should I do so it will be part of the war, thus clients can
>> access it via "http://path.to/appname/images/someimage.jpg"?
>>
>> What is the best practice on this?
>>
>> Thank you so much.
>> Sam
>
>
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