Thanks for your help!

Seems that there isn't a general solution to this...

(Nice tip on checking exist(), I pulled my hair out a few times when I 
forgot to create the folders!)

On Thursday, April 5, 2012 2:35:59 AM UTC+8, Matias Costa wrote:
>
> In web.xml:
>
> <servlet>
>     <servlet-name>imageReceiver</servlet-name>
>     <servlet-class>xxx.ImageReceiver</servlet-class>
>     
>     <init-param>
>         <param-name>imagePath</param-name>
>         <param-value>/the/place</param-value><!-- or C:\the\place -->
>     </init-param>
> </servlet>
>
> And in the servlet:
>
> public void init(ServletConfig servletConfig) throws ServletException{
>     imagePath = servletConfig.getInitParameter("imagePath");
>     if (!imagePath.endsWith(File.separator)) imagePath += File.separator
>     try {
>         File imageFolder = new File(imagePath);
>         if (!File.exists()) Util.mkdirRecursive(imagePath);
>     } catch ... whatever you want to do if something fails
>   }
>
> El martes 3 de abril de 2012 03:21:06 UTC+2, Sam W escribió:
>>
>> Hello, 
>>
>> I haven't been able to figure this out after spending 3 hours on 
>> Google. 
>>
>> I can fetch an image, but I don't know where to put them. 
>> If I just use "new File("image.jpg")", it will end up in my tomcat 
>> bin/ folder. 
>>
>> Some sugggests to use getServletContext().getRealPath("/"); but it 
>> would block forever at "getServletContext", I don't know why. 
>>
>> What should I do so it will be part of the war, thus clients can 
>> access it via "http://path.to/appname/images/someimage.jpg";? 
>>
>> What is the best practice on this? 
>>
>> Thank you so much. 
>> Sam
>
>

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