On Monday, March 25, 2013 11:23:51 AM UTC+1, rkulisas wrote:
>
> //josn is {"name":"item_name","index":0,*"text":"Kindle Fire HD 8.9\"..."*
> }
>
> JSONValue value = JSONParser.parseStrict(json);
>
> JSONObject obj;
>
> JSONString name, text;
>
> JSONNumber nxd;
>
> if ((obj = value.isObject()) == null ) return null;
>
> if ((value = obj.get("name")) != null)
>
> if ((name = value.isString()) != null)
>
> field.setName(name.stringValue());
>
> if ((value = obj.get("text")) != null)
>
> if ((text = value.isString()) != null){
>
> System.out.println("VALUE:" + value.toString()); //VALUE:"Kindle Fire
> HD 8.9\" ..."
>
> System.out.println("TEXT:" + text.stringValue()); //TEXT:Kindle Fire HD
> 8.9" ...
>
> field.setText(text.stringValue());
>
> }
> Am I supposed to use JSONValue.toString() to get my string value instead?
> Why JSONString.stringValue() doesn't parse properly?
>
The question is more: why do you want the \ to be there?
It's in your JSON because JSON uses " to markup string literals and thus
has to escape " that appears within the string value, just like you do in
Java or JavaScript or so many other languages (C, etc.)
stringValue() *does* return the correct value, it's just that you're
expecting something else.
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