On 12/17/2012 11:59 AM, Guillaume Gay wrote: > Is there a way to do the following differently: > > edge_x = g.new_edge_property() > edge_x.a = np.array([x[e.source()] for e in g.edges()]) > > with x being a vector property map. > I plain English, is there a (more efficient) way to copy the vertex property > map of every edge source to an edge property map?
Something like this is not yet available, you have to use a python loop for now. However I plan to add something like this at some point, since it occurs often enough. If you wish, you may open a ticket, and I'll address when time permits. Cheers, Tiago -- Tiago de Paula Peixoto <[email protected]>
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