Glynn Clements wrote:

> Alternatively, the r.cross
> step could be done with r.mapcalc as e.g.:
> 
>       r.mapcalc 'result = map1 * 100 + map2'
> 

Thanks for the hint. I should have thought about it myself.

> 
> r.mapcalc doesn't do short-circuit evaluation, which is why long
> "if-else" chains are slow.
> 

Which is a pity in my case. But luckily, I just learned how to avoid long 
if-else chains.

Thanks for your time,  

Hermann
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