Ah ok Glynn, I always meant logical operators. Probably I copied the error from a different test.
If logical operator is applied to, sat, Byte data it gives true/false results, e.g. if(A && B,1, 0) behaves correctly even with cell values values greater then 1. That's why I expected it to work with floats operands too. >From a user perspective if it works for a cell with value 2 it should also work for a cell with value 2.0. That'all. giovanni Il 22/ott/2015 02:44, "Glynn Clements" <[email protected]> ha scritto: > > G. Allegri wrote: > > > > This isn't about the if() function. The bitand() function (to which > > > the error message refers) corresponds to the bitwise-and operator "&". > > > > > > The if() function accepts either integer or floating-point values for > > > its arguments. > > > > That's what disappointed my client (and me) Glynn: why integer yes and > not > > floats? Is it a technical limitation or there's a ratio behind it? > > Anyway did I miss something from the docs? I couldn't find it. > > What would you expect the value of (x & y) to be if x and/or y were > floating-point values? > > > Why do you that I'm confusing the operators? I've always talked about > > logical operators... > > Because you quote an error message which specifically refers to a > *bitwise* operator: > > > "Incorrect argument types to function bitand()". > > in a message which otherwise only mentions logical operators. > > "bitand()" is the name of the bitwise-and function, which corresponds to > the infix "&" operator. I.e. (x & y) is exactly equivalent to bitand(x, y). > > This is the same as the "&" operator in C or C++: it evaluates to an > integer where each bit in the result is set (one) if the corresponding > bit is set in both operands, and unset (zero) otherwise. E.g. (23 & 34) > is > 00010111 (23) > & 00100010 (34) > -------- > = 00000010 ( 2) > > Perhaps it would help if you posted the exact expression which is > causing you problems. > > -- > Glynn Clements <[email protected]> >
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