Gabriel Cotlier wrote:

    I'm using grass 7.4.1 trying to export  all raster layers in the current
    mapset out of grass to a folder as GeoTiff files though a for loop from
    the python shell  as follows and I'm getting the error in red...
    What could be the problem?
    Thanks a lot in advance.
    Regards,
    Gabriel
    >>>import grass.script as gscript
    >>>rastlist=grass.read_command("g.list",type="rast")
    >>>rastlist
    F121996
    F121997
    F141999
    F142000

Micha Silver:
  Try:
  rastlist=grass.read_command("g.list",type="rast").split()

[..]

For me it works like:

rasters=grass.read_command('g.list', type='raster', 
separator='comma').split(',')

I wonder why the 'comma' is not mentioned for the separator option, when
asking for the module's help:
```
Lists available GRASS data base files of the user-specified data type 
optionally using the search pattern.

Usage:
g.list [-iretmpf] type=datatype[,datatype,...] [pattern=string]
  [exclude=string] [mapset=name[,name,...]] [separator=character]
  [region=name] [output=name] [--overwrite] [--help] [--verbose]
  [--quiet] [--ui]

Flags:
 -i   Ignore case
 -r   Use basic regular expressions instead of wildcards
 -e   Use extended regular expressions instead of wildcards
 -t   Print data types
 -m   Print fully-qualified map names (including mapsets)
 -p   Pretty printing in human readable format
 -f   Verbose listing (also list map titles)

Parameters:
      type   Data type(s)
             options: raster,raster_3d,vector,label,region,group,all
   pattern   Map name search pattern (default: all)
   exclude   Map name exclusion pattern (default: none)
    mapset   Name of mapset to list (default: current search path)
 separator   Field separator
             default: newline
    region   Name of saved region for map search (default: not restricted)
    output   Name for output file
```

This on
```
g.version -r
GRASS 7.5.svn (2018)
libgis Revision: 72327
libgis Date: 2018-03-06 12:12:44 +0100 (Tue, 06 Mar 2018)
```

Nikos

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