Re: [Gretl-users] inlist()-problem

[artur tarassow]

Ah ok, I think I got it, Allin. Thank you for the workaround.

Cheers,
Artur


2013/4/19 Allin Cottrell <cottrell(a)wfu.edu>

> On Fri, 19 Apr 2013, artur tarassow wrote:
>
> > I've got another problem,
> >
> > I am trying check whether the variable "time" is present in list L1. This
> > correct position is shown in the first example below. But if I add this
> > inlist-command to a function environment, the scalar check2 = 0 but
> should
> > be 2. I am using gretl (built: 2013-03-17) on Windows.
> >
> > <hansl>
> > set messages off
> > set echo off
> > open denmark --quiet
> >
> > #Works
> > ols LRM const time diff(LRM)
> > L1 = $xlist
> > scalar check1 = inlist(L1,const)
> > check1
> > scalar check2 = inlist(L1,time)
> > check2
> >
> > #Within a function check2 gives the wrong result
> > ols LRM const time diff(LRM)
> > L1 = $xlist
> > function void Ltest (list L)
> >    scalar check1 = inlist(L,const)
> >    print check1
> >    scalar check2 = inlist(L,time)
> >    print check2
> > end function
> > Ltest(L1)
> > </hansl>
>
> This is rather confusing, admittedly, but it's not exactly a
> bug. The point is that series supplied to a function via a
> list argument are in a different namespace from series defined
> within the function. This would be more apparent if you tried
>
> scalar check = inlist(L, d_LRM)
>
> inside your function: you'd get an error, because the series
> d_LRM is not "visible" as such within the function.
>
> I'll think about this issue some more (and how best to resolve
> and/or document it). But in the meantime you can do the test
> you want by iterating over the list, as in
>
> <hansl>
> function void Ltest (list L)
>    loop foreach i L
>      if "$i" == "time"
>        printf "time: list position = %d\n", i
>      endif
>    endloop
> end function
> </hansl>
>
> Allin
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>

Ah ok, I think I got it, Allin. Thank you for the workaround.

Cheers,

Artur

2013/4/19 Allin Cottrell <cottr...@wfu.edu>

On Fri, 19 Apr 2013, artur tarassow wrote:

> I've got another problem,
>
> I am trying check whether the variable "time" is present in list L1. This
> correct position is shown in the first example below. But if I add this
> inlist-command to a function environment, the scalar check2 = 0 but should
> be 2. I am using gretl (built: 2013-03-17) on Windows.
>
> <hansl>
> set messages off
> set echo off
> open denmark --quiet
>
> #Works
> ols LRM const time diff(LRM)
> L1 = $xlist
> scalar check1 = inlist(L1,const)
> check1
> scalar check2 = inlist(L1,time)
> check2
>
> #Within a function check2 gives the wrong result
> ols LRM const time diff(LRM)
> L1 = $xlist
> function void Ltest (list L)
>    scalar check1 = inlist(L,const)
>    print check1
>    scalar check2 = inlist(L,time)
>    print check2
> end function
> Ltest(L1)
> </hansl>

This is rather confusing, admittedly, but it's not exactly a
bug. The point is that series supplied to a function via a
list argument are in a different namespace from series defined
within the function. This would be more apparent if you tried

scalar check = inlist(L, d_LRM)

inside your function: you'd get an error, because the series
d_LRM is not "visible" as such within the function.

I'll think about this issue some more (and how best to resolve
and/or document it). But in the meantime you can do the test
you want by iterating over the list, as in

<hansl>

function void Ltest (list L)

   loop foreach i L
     if "$i" == "time"
       printf "time: list position = %d\n", i
     endif
   endloop
end function
</hansl>

Allin
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