The actual output of the script would be much more helpful, as would a
link to the page that's being output. Not really much to comment on
on your code there...
Tyler
On Oct 21, 8:16 am, Bjorn <[EMAIL PROTECTED]> wrote:
> Hi there,
>
> I've successfully managed to make an ajax call, created the code to
> display the greybox images and update a div from the page calling the
> script. My problem is when I try to use the showImageSet and
> dynamically build the image_set var in my php page. It shows a gallery
> of 4 images which is right, but no actual images display. I get the
> image paths and file names from a mysql db.
>
> Here's my code
>
> $image_set = "[{'caption': 'Image 1', 'url': '".images/projects/
> $project->project_folder/$project->image1."'},";
> $image_set .= " {'caption': 'Image 2', 'url': '".images/projects/
> $project->project_folder/$project->image2."'},";
> $image_set .= " {'caption': 'Image 3', 'url': '".images/projects/
> $project->project_folder/$project->image3."'},";
> $image_set .= " {'caption': 'Image 4', 'url': '".images/projects/
> $project->project_folder/$project->image4."'}]";
>
> $html .= "<a
> href=\"images/projects/$project->project_folder/$project->image1\"
> onclick=\"return GB_showImageSet($image_set, 1)\">Click me</
>
> a>";
>
> echo $html;
>
> Thanx for help in advance
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