Thanks Mark. As a follow up, how does the server differentiate between this case and the scenario when the upper layer doesn't register again?
On Wednesday, March 25, 2020 at 10:49:59 AM UTC-7, Mark D. Roth wrote: > > No, the incoming request will be queued by the server. > > On Mon, Mar 23, 2020 at 10:24 AM Sumukh Shivaprakash <[email protected] > <javascript:>> wrote: > >> I have a newbie question on grpc server handlers in c++. >> >> The greeter example shows how the server requests for an API by >> registering a "RequestSayHello()" and on receiving a request from a client, >> creates a new object that registers another "RequestSayHello()" for >> subsequent requests, after which it starts processing the first one. >> >> My question is: >> In the event of a delay (e.g. context switch) before registering the new >> "RequestSayHello()", what is the behavior if the client sends another >> request message? Is it rejected by the server because there are no >> registered handlers? >> >> -- >> You received this message because you are subscribed to the Google Groups >> "grpc.io" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to [email protected] <javascript:>. >> To view this discussion on the web visit >> https://groups.google.com/d/msgid/grpc-io/f934fa06-2d68-40ea-ba74-affb1f6d6228%40googlegroups.com >> >> <https://groups.google.com/d/msgid/grpc-io/f934fa06-2d68-40ea-ba74-affb1f6d6228%40googlegroups.com?utm_medium=email&utm_source=footer> >> . >> > > > -- > Mark D. Roth <[email protected] <javascript:>> > Software Engineer > Google, Inc. > -- You received this message because you are subscribed to the Google Groups "grpc.io" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/grpc-io/dedf886b-d606-4b84-bc58-cbe83dfaa1dc%40googlegroups.com.
