Hi amits, 

Sorry for the late replay.
I have write a minimal example to express my question.
https://gist.github.com/codingbaobao/f89291866024a97c1b476a682f82c029

The main purpose is trying to manage request&response header in 
interceptor, in order to share come context or status.
I have try metadata.FromIncomingContext() and seems empty.
Is there have any method to send request header first without sending 
payload?
Since this concept is documented in 
here: https://grpc.io/docs/what-is-grpc/core-concepts/#unary-rpc
Or, any method that can let me access response header without wrapping a 
ClientStream?
thanks!
[email protected] 在 2022年4月1日 星期五上午5:49:54 [UTC+8] 的信中寫道:

> Have you tried the metadata.FromIncomingContext() function?
>
> You haven't shared your example code - i think that will be useful for 
> others to help you.
>
>
>
>
>
> On Thursday, March 31, 2022 at 3:44:02 PM UTC+11 [email protected] wrote:
>
>> Hi all,
>>
>> Currently I have a rpc like this:
>> *rpc SayHello (HelloRequest) returns (stream HelloReply) {}*
>>
>> Now I add a StreamClientInterceptor to catch response initial metadata,
>> but it block forever, and server shows that no request get, at least not 
>> into the rpc function.
>>
>> The interceptor is similar to this example:
>>
>> https://github.com/grpc/grpc-go/blob/master/examples/features/interceptor/client/main.go#L90
>> and I just add a line under L107 :
>> *responseMeta, err := s.Header()  //<-- block here*
>>
>> Im sure that I can done in Python code,  which is implement similar to:
>>
>> https://github.com/grpc/grpc/blob/master/examples/python/interceptors/headers/generic_client_interceptor.py#L33
>> and adds code under L37:
>> *print(response_it.initial_metadata())*
>>
>> Can anyone tell me what is wrong of my Golang code?
>> Actually I can get header by wrapping grpc.ClientStream and received in 
>> RecvMsg()
>> and I observed that I can only get header after SendMsg, but it doesn't 
>> make sense :(
>>
>

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