> On Wed, Jan 31, 2001 at 03:30:57PM -0200, Flavio Ribeiro wrote:
> > b. The easy way: run strtof() on the string and see if it returns 0. If it
> > does, the user either entered '0' or entered something illegal. Read
> > strtof's man page for more ideas.
>
> % man strtof
> No manual entry for strtof
> % uname -sr
> FreeBSD 3.4-RELEASE
>
> On the other hand:
>
> % man strtod
>
I'm sorry, I actually meant strtod(). There's no strtof. The question's author
prompted for a float and that got me going without thinking, specially since
atof() actually returns a double.
>
> Note also that if you hand "strtod()" the string "6.02e23qqqq", it will
> return 6.02e+23, not 0.0 - i.e., it doesn't treat extra characters at
> the end of the string as an error (presumably because the intent is that
> it can be used to carve numeric tokens out of a string).
>
Yes, but it will return 0 if you present the string "qqqqq6.02e23" or even
"qqqqqqqqq" and you'll have to be prepared for such an input [as you comment
later on]
Flavio
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