Show window for a few seconds and delete it?

[george carter]

The "gtk_timeout_add"  that Paul posted sounds like what I might be looking 
for.  I think I might want to delete the window and not just hide it though. 
I figure by hiding it, it will still reside in memory. I couldn't find the 
"gtk_timeout_add" in the Gnome Api Reference.  If anyone has any idea how I 
might go about using it I would appreciate it.  I used the the source code 
below just to keep it as simple as possible.  But I'm still unsure where 
exactly to place it in the code and it's format.  Initially, I thought it 
would be as easy as showing the window, creating a loop count, and calling 
"gtk_window_destroy" for example.  I'm new to gtk programming so I might 
need a little "hand holding" on this example.

/* basicgtk.c */

#include <gtk/gtk.h>

  /* Function which stops the program */
  void CloseTheApp(GtkWidget * window, gpointer data )
  {
     gtk_main_quit ();
  }
gint main ( gint argc, gchar * argv[] )
{
  /* Declare a GtkWidget to use as the main window */
  GtkWidget * window ;
  /* Start GTK+ up, and let it process any arguments that were */
  /* passed in on the command line */
  gtk_init ( &argc, &argv );
  /* Create the window itself */
  window = gtk_window_new ( GTK_WINDOW_TOPLEVEL ) ;
  gtk_signal_connect(GTK_OBJECT(window),
    "destroy",
     GTK_SIGNAL_FUNC(CloseTheApp),
     NULL);
  /* Show the window, as far as GTK+ is concerned though we just want */
  /* to make a widget visible */
  gtk_widget_show (window);
  /* Start GTK+ running so that it can catch any signals */
  gtk_main () ;
  /* This line will never be reached in this app */
  return 0;
}
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