>
> if (condition):
> glib.timeout_add(i,f)
>
> def f:
> (...)
> i = (....)
> (condition)
> return True
>
> Even the value of "i" is different each time I call "f",
> glib.timeout_add(i,f) call "f" always with the same value of "i".
>
Changing the value of "i" will not change the timeout because it was
already called and the value of "i" was copied there when passing the
parameter. You must call the timeout again like this:
if (condition):
glib.timeout_add(first_timeout, f)
def f:
(...)
i = (....)
if (condition):
glib.timeout_add(i, f) # This will start another timeout with the new
interval
return False # This will end this timeout!
Regards,
Ian L. Rodrigues
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