Hi, Stefan Israelsson Tampe <stefan.ita...@gmail.com> skribis:
> (define (c-equal-1 x y) > (match x > (((and xx (_ . _)) . _) [...] > ((xx . _) [...] > (_ (equal? x y)))) Doesn’t this mean that ‘cycle-equal?’ falls back to ‘equal?’ for non-pairs? Ludo’.
