> There's a newer version of Matplotlib which has a reference cycle matplotlib 
> <- ipython <- matplotlib. Sigh...

If I remove "ipython requires matplotlib" (according to matplotlib upstream it 
doesn't - at least they imply that), then still this remains:

python-numpy requires python-matplotlib
python-matplotlib requires python-numpy-bootstrap
python-matplotlib requires python-ipython
python-ipython requires python-numpy

Therefore, there's a cycle

python-ipython requires python-numpy requires python-matplotlib requires 


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