Let's verify if I've understood:
if I have a line long 1000 nm, scanned with 256 points, then I'll have a 
pixel of approximately 3,9 nm
if I choose a cut-off of 0,12 It means that I'm cutting informations 
taken with a step more than 65 nm?
Palma D'Antonio


Il 15/03/2011 16:37, David Necas (Yeti) ha scritto:
> On Tue, Mar 15, 2011 at 03:52:39PM +0100, Palma D'Antonio - Unifg wrote:
>>    I'm sorry, I think we are talking of different things.
> Probably.
>
>> I mean that
>> using the 'roughness tool' (ISO button) we select a cut-off value in
>> order to filter our data (digitalized using a DFT function as you
>> previously reported). This cut-off frequency value should be the inverse
>> of a parameter measured in meters that we can call 'sampling step'
>> (different from tha scan step).,
> The profile is a discrete signal sampled with spatial step Δ which is
> conceptually different from the scan step but, as I explained, chosen to
> be equal.  I.e. Δ is the lateral distance between the neighbour points
> in the profile (and this happens to be the same as the pixel size).
>
> The cut-off C is then relative to the spatial frequency 1/(2Δ).  I.e. a
> cut-off of 1.0 would mean all frequencies (up to the Nyquist frequency
> which in DFT sense means simply all because of the mixing of the
> low-frequency and high-frequency halves of the spectrum) are included.
>
> So if I understand correctly your definition of sampling step it is
> 2Δ/C.
>
> Regards,
>
> Yeti
>
>
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-- 
Palma D’Antonio
Laboratorio di fisica applicata
Dipartimento di scienze biomediche
Università degli studi di Foggia
Tel e fax 0881 732086


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