Hi,

Thanks a lot for the test case! A simpler test case is:

drop table test;
create table test(id int, name varchar);
insert into test values(1, 'a');
(select id from test order by id)
union (select id from test order by name);

Regards,
Thomas



On Thu, Dec 26, 2013 at 9:57 PM, Ilya Belopolsky
<[email protected]>wrote:

> forgot attachment in original post
>
>
> On Tuesday, December 24, 2013 12:24:05 PM UTC-5, Ilya Belopolsky wrote:
>>
>> When I execute the following command:
>>
>> (SELECT employee_id FROM employees ORDER BY employee_id)
>>
>> union
>>
>> (select employee_id FROM job_history ORDER BY job_id);
>>
>>
>> I have attached a sql script to reproduce the schema, tables, and data
>>
>>
>> The result set contains duplicates as if I used the "union all" command.  
>> Even if I use "union disctinct" explicitly, i get duplicates.
>>
>>
>> The issue is related to the ORDER BY clause in the second select.  The issue 
>> goes away if I use the column in the select clause (employee_id) as the 
>> order by column, but the same issue is present with any other column in the 
>> order clause.
>>
>>
>> The issue is present regardless of the position of the Select subquery.
>>
>>
>> Is this a bug or am I missing something?
>>
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