2013/12/29 Cecil Westerhof <[email protected]>
>
> 2013/12/29 Noel Grandin <[email protected]>
>
>> SELECT *
>> FROM mytable
>> WHERE col1 != STRINGENCODE(col1)
>>
>
> Works great, thanks. It only also finds ", but can live with that. I just
> had one table updated. With this statement I found one I had not done
> correctly.
>
To make it ‘perfect’ I now use:
WHERE STRINGENCODE(col1) LIKE '%\\u%'
Now I get exactly what I need.
--
Cecil Westerhof
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