I got an example:
try compiling this code:
#include <stdio.h>
int
main(void)
{
printf("%d", sizeof unsigned char);
return (0);
}
you will probably get a compiler error like this:
sizeof.c: In function ‘main’:
sizeof.c:6:22: error: expected expression before ‘unsigned’
printf("%d", sizeof unsigned char);
^~~~~~~~
However, with parenthesies:
#include <stdio.h>
int
main(void)
{
printf("%d\n", sizeof(unsigned char));
return (0);
}
It will compile successfully.
Hope you got the idea
Raiz
On 2016-09-05 10:25, FRIGN wrote:
On Mon, 5 Sep 2016 07:42:36 +0200
Anselm R Garbe <[email protected]> wrote:
Hey Anselm,
Quick note: your syntax usage of sizeof is not 100% accurate.
Use 'sizeof(type)' with brackets but 'sizeof var' without.
I use sizeof always function-like and see no reason why I shouldn't use
"sizeof(var)" and instead use "sizeof var". It doesn't alter the code
behaviour and ultimately it's all about readability.
If you eyes have become accustomed to always use function-like syntax
for such operators the best bet is not to break this style because it's
not "necessary" to have parentheses for variable sizeof's.
Cheers
FRIGN
