Try:
%table
- (1..6).to_a.in_groups_of(3) do |row|
%tr
- row.each do |col|
%td= col
I haven't actually *tried* this, but it seems it should work.
On Sep 6, 2009, at 4:57 PM, Tim W wrote:
>
> How does one do this in Haml?
>
> Say I have an array [1,2,3,4,5,6] and I want a table like...
>
> <table>
> <tr>
> <td>1</td>
> <td>2</td>
> <td>3</td>
> </tr>
> <tr>
> <td>4</td>
> <td>5</td>
> <td>6</td>
> </tr>
> </table>
>
> I have done it may times, but never in haml..
>
> %table
> - [1,2,3,4,5,6].each_with_index do |n,i|
> - if i%3 == 0
> %tr
> %td= n
>
> This gives a result of...
>
> <table>
> <tr></tr>
> <td>1</td>
> <td>2</td>
> <td>3</td>
>
> <tr></tr>
> <td>4</td>
> <td>5</td>
> <td>6</td>
> </table>
>
> How do I get the tr to wrap the 3 td's?
>
>
>
> >
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